Hi, All
here is not a full version script, just post a sample.
#/bin/bash
read -p 'Addr: ' addr
sed 's/<Address>/'"$addr"'/' pf.mod>$1
If the input string include `/', sed will return error message. I know that s/// can be replaced with s::: or s!!!, etc, but the input var can accept... (4 Replies)
how can i only display the result according to user input?
For example:
i have a data file(in the attachement), when the user enter "1" it will only display whole records with pid from the data file matches to the users entered. (13 Replies)
Hi,
On using GDB debugger on different executables, the address displayed for the symbols seem incorrect, as it shows me the same address in each prorgram, run simultaneoulsy.
eg:
Program: linkmain1.c
Breakpoint 1, main () at linkmain1.c:14
14 printf("In linkmain1.c\n");
(gdb)... (0 Replies)
Hi,
How do I parse/split lines (strings) read from a file and display the individual tokens in a shell script? Given that the length of individual lines is not constant and number of tokens in each line is also not constant.
The input file could be as below:
... (3 Replies)
Hi,
The following error message occured when I was trying to reboot my SUN machine:
Memory address not aligned
Its a Sun 280 R , Ultra SPARC III
What should I do.
Varma (3 Replies)
Hi all,
I wrote a script that reads inputs from user and store in array named "input". The number of elements in the array is not fixed - determined only after user exit the while loop that reads the array values :
x=1
echo "Enter first value"
read input
while } != "exit" ]
do
... (1 Reply)
hi
can anyone fine a solution thwe the problem that am facing
i was trying to install sun4v client vth sol10_U8,
but when i played "boot net"
its asking for "requesting internet address for 0:21:28:17:80:f4
plz give me a sol for this (1 Reply)
Hi, i am very new to php Is it possible to display Range of date depend on user input day
example:
user input 2 day start from 28/4/12 it will add 2 day from date of input
so display should look like this
28/4/12 to 30/4/12
then from 30/412 user add another 4 date so will... (0 Replies)
Hi ,
I am getting error in bind function of "Address already in use" even also i have used the setsockopt function in that case .
Please help
int ret = 0;
int listenSock = 0;
struct sockaddr_in myAddr;
struct sockaddr_in ... (1 Reply)
I have a flat file that contains a list of IP address following 6 additional lines.
I would like to get a help in the following. a shell script that would take ip address or list of ip addresses as input, search one by one the ip address in the file and as soon as it find the exact match it... (12 Replies)
Discussion started by: knijjar
12 Replies
LEARN ABOUT PHP
datetime.add
DATETIME.ADD(3) 1 DATETIME.ADD(3)DateTime::add - Adds an amount of days, months, years, hours, minutes and seconds to a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::add (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_add (DateTime $object, DateInterval $interval)
Adds the specified DateInterval object to the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.add(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-01');
date_add($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-11
Example #2
Further DateTime.add(3) examples
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-01 10:00:30
2007-06-05 04:03:02
Example #3
Beware when adding months
<?php
$date = new DateTime('2000-12-31');
$interval = new DateInterval('P1M');
$date->add($interval);
echo $date->format('Y-m-d') . "
";
$date->add($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-01-31
2001-03-03
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.sub(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.ADD(3)