Sponsored Content
Full Discussion: Number of users in passwd
Top Forums Shell Programming and Scripting Number of users in passwd Post 302402546 by Jairaj on Wednesday 10th of March 2010 05:27:51 AM
Old 03-10-2010
Try this :-
Code:
awk -F':' '{ print $3}' /etc/passwd   | sort  | uniq -c


Last edited by pludi; 03-10-2010 at 06:34 AM.. Reason: code tags, please...
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

Maximum number of users allowed

How do i determen (what command) the max. number of users allowed Thanks in advance (10 Replies)
Discussion started by: siza
10 Replies

2. Shell Programming and Scripting

append 3 users in /etc/passwd

I am looking to add 3 lines in /etc/passwd via a script. Can you please give me an idea on how to write a script that can do that? (3 Replies)
Discussion started by: melanie_pfefer
3 Replies

3. UNIX for Dummies Questions & Answers

editing sqlplus id@passwd in multiple scripts, users and directories

hi all, i was given by my supervisor a task to search for scripts which contain oracle sqlplus i.e "myusername/mypasswd @myDB" in every /home/userfolder, which are, all the scripts made by different user. I've done some find command to search string for sqlplus, but it may up too long to respond.... (8 Replies)
Discussion started by: Helmi
8 Replies

4. Shell Programming and Scripting

to find the number of users logged in

Hi, can u say to display the number of users that logged before me. thanks (10 Replies)
Discussion started by: shanshine
10 Replies

5. Solaris

Defaults number of users and Groups

Hi All, I would like know how many of default number of users and groups are there in solaris-10... Regards Tirupathi Raju (2 Replies)
Discussion started by: tirupathiraju_t
2 Replies

6. Shell Programming and Scripting

number of users logged in script

My admin needs a shell script in Korn that will show conditions based on users logged in. I have never used the Korn shell and have no clue what I am doing, can anyone help. here are the conditions that need to be returned. if users are below 5 displays should be: performance is high if... (1 Reply)
Discussion started by: vthokiefan
1 Replies

7. Shell Programming and Scripting

Number of users problem

Hi. I have a problem with my homework. I have to do a Script that will tell me the number of users that are logged in on my system through a network and find out their IP's. Can you give me an idea? Thanks (1 Reply)
Discussion started by: mitzu
1 Replies

8. Shell Programming and Scripting

Removing old user directories that are no longer Users in /etc/passwd

I am new to shell scripting, and have not done much programming in several years. So I am very rusty at this at best. I know my way around the linux command line, but actually scripting is something I have not done too much of. I have been tasked to come up with a script that will pull all... (5 Replies)
Discussion started by: shuiend
5 Replies

9. Solaris

Impact on existing users when changing passwd defaults

Hi Administering Solaris Systems - Solaris 10 mostly. If I change the /etc/default/passwd settings - E.G. to increase minimum passwd length, then what happens to existing users with passwords shorter than this. presumably they are not affected until next time they want to change password. ... (4 Replies)
Discussion started by: Mudshark
4 Replies

10. Solaris

Can't change users passwd

Have an issue with a user or root changing the user's passwd. We run the passwd command and a complex passwd is entered a message is displayed, "passwd is based on a dictionary word." We do have a dictionary file and I know for a fact the complex passwd is not in the list. This happens on a... (3 Replies)
Discussion started by: solizkewl
3 Replies
JOIN(1) 						      General Commands Manual							   JOIN(1)

NAME
join - relational database operator SYNOPSIS
join [ options ] file1 file2 DESCRIPTION
Join forms, on the standard output, a join of the two relations specified by the lines of file1 and file2. If file1 is `-', the standard input is used. File1 and file2 must be sorted in increasing ASCII collating sequence on the fields on which they are to be joined, normally the first in each line. There is one line in the output for each pair of lines in file1 and file2 that have identical join fields. The output line normally con- sists of the common field, then the rest of the line from file1, then the rest of the line from file2. Fields are normally separated by blank, tab or newline. In this case, multiple separators count as one, and leading separators are dis- carded. These options are recognized: -an In addition to the normal output, produce a line for each unpairable line in file n, where n is 1 or 2. -e s Replace empty output fields by string s. -jn m Join on the mth field of file n. If n is missing, use the mth field in each file. -o list Each output line comprises the fields specifed in list, each element of which has the form n.m, where n is a file number and m is a field number. -tc Use character c as a separator (tab character). Every appearance of c in a line is significant. SEE ALSO
sort(1), comm(1), awk(1) BUGS
With default field separation, the collating sequence is that of sort -b; with -t, the sequence is that of a plain sort. The conventions of join, sort, comm, uniq, look and awk(1) are wildly incongruous. JOIN(1)
All times are GMT -4. The time now is 07:24 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy