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Full Discussion: Reuse Variable..
Top Forums Shell Programming and Scripting Reuse Variable.. Post 302401844 by aimy on Monday 8th of March 2010 04:13:05 AM
Old 03-08-2010
Bug

Quote:
Originally Posted by anchal_khare
you want to repeat the task with 3 cvs then you can use a loop too..

Code:
for CV in CV000 CV09
do
 file_name="CP99978_${CV}.TXT"  ## no need of command substitution here 
 ## do sqlldr part..or other stuffs.
done

just for info:
Code:
cv="$(echo "CV000")"

is equivalent to
Code:
cv="CV000"

Thank you so much!!

Finally, a great command generalization.. Smilie

But anyway, I still curious, why if we set it normally, that $file_name variable won't take the latest value assigned to the $cv? Smilie
 

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ESCAPESHELLARG(3)							 1							 ESCAPESHELLARG(3)

escapeshellarg - Escape a string to be used as a shell argument

SYNOPSIS
string escapeshellarg (string $arg) DESCRIPTION
escapeshellarg(3) adds single quotes around a string and quotes/escapes any existing single quotes allowing you to pass a string directly to a shell function and having it be treated as a single safe argument. This function should be used to escape individual arguments to shell functions coming from user input. The shell functions include exec(3), system(3) and the backtick operator. On Windows, escapeshellarg(3) instead removes percent signs, replaces double quotes with spaces and adds double quotes around the string. PARAMETERS
o $arg - The argument that will be escaped. RETURN VALUES
The escaped string. EXAMPLES
Example #1 escapeshellarg(3) example <?php system('ls '.escapeshellarg($dir)); ?> SEE ALSO
escapeshellcmd(3), exec(3), popen(3), system(3), backtick operator. PHP Documentation Group ESCAPESHELLARG(3)
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