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Full Discussion: Shell program with username and password
Top Forums UNIX for Dummies Questions & Answers Shell program with username and password Post 302398712 by thedemonhunter on Thursday 25th of February 2010 02:02:27 PM
Old 02-25-2010
vivekraj, you seem to understand what i need to do. I attempted something similar but i was having trouble comparing the two (username and password). What if i wanted to do this for multiple users? Would i use a CASE statement? such as:

Code:
case $username in
    alex ) pass=alex2;;
    sean ) pass=sean2;;
    ashley ) pass=ashley2;;
    # *) echo "error"
esac

But then i'm thinking this would affect the whole code and you would need the names as such: alex | sean | ashley.

What do you guys think?

---------- Post updated at 11:35 AM ---------- Previous update was at 10:51 AM ----------

also guys, this is what i had so far. i know it's wrong (especially the * part, it doesn't work) but like i said i am very new to this. i was trying to do this for one user first but i actually want to do multiple like i mentioned.

Code:
#!/bin/sh

echo "Enter login name and password"
read trythis

if [ $trythis = "Aarin_dtfc" ]
then
	echo "You are logged in!"
else [ $trythis = "Aarin_*" ]
	echo "Wrong password!"
	exit 1
else [ $trythis = "*_dtfc" ]
	echo "Login name is not recognized!"
	exit 2
fi
exit 0



---------- Post updated at 02:02 PM ---------- Previous update was at 11:35 AM ----------

ok i rewrote the code to this:

Code:
#!/bin/sh
echo "Enter username"
read username
if [ $username = "Aarin" ]
then  
 echo Enter password
 read password
case $username in
 Aarin ) pass=dtfc;;
 Rick ) pass=unpo
esac
while [ "$password" != "$pass" ]; do
 echo "Wrong password!"
 return 1
done
echo "You are logged in!" 
return 0
else
 echo "Login name not recognized"
fi
return 2

the only thing i am having trouble doing is adding multiple usernames to the if statement
Last edited by pludi; 02-25-2010 at 04:17 PM.. Reason: Please use code tags.......
 

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LEARN ABOUT SUNOS

list-connector-connection-pools

asadmin-list-connector-connection-pools(1AS)			   User Commands		      asadmin-list-connector-connection-pools(1AS)

NAME

       asadmin-list-connector-connection-pools, list-connector-connection-pools - gets all the connection pools

SYNOPSIS

       list-connector-connection-pools	--user admin_user [--password admin_password] [--host localhost] [--port 4848] [--secure |-s] [--password-
       file filename] [--terse=false] [--echo=false] [--interactive=true]

       gets all the connector connection pools. This command is supported in remote mode only.

OPTIONS

       --user		       authorized domain application server administrative username.

       --password	       password to administer the domain application server.

       --host		       machine name where the domain application server is running.

       --port		       port number of the domain application server listening for administration requests.

       --secure 	       if true, uses SSL/TLS to communicate with the domain application server.

       --passwordfile	       file containing the domain application server password.

       --terse		       indicates that any output data must be very concise, typically avoiding human-friendly sentences and favoring well-
			       formatted data for consumption by a script. Default is false.

       --echo		       setting to true will echo the command line statement on the standard output. Default is false.

       --interactive	       if set to true (default), only the required password options are prompted.

       Example 1: Using list-connector-connection-pools

       asadmin> list-connector-connection-pools --user admin
       --password adminadmin

EXIT STATUS

       0		       command executed successfully

       1		       error in executing the command

       asadmin-create-connector-connection-pool(1AS), asadmin-delete-connector-connection-pool(1AS)

J2EE 1.4 SDK							    March 2004			      asadmin-list-connector-connection-pools(1AS)
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