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Full Discussion: Shell program with username and password
Top Forums UNIX for Dummies Questions & Answers Shell program with username and password Post 302398712 by thedemonhunter on Thursday 25th of February 2010 02:02:27 PM
Old 02-25-2010
vivekraj, you seem to understand what i need to do. I attempted something similar but i was having trouble comparing the two (username and password). What if i wanted to do this for multiple users? Would i use a CASE statement? such as:

Code:
case $username in
    alex ) pass=alex2;;
    sean ) pass=sean2;;
    ashley ) pass=ashley2;;
    # *) echo "error"
esac

But then i'm thinking this would affect the whole code and you would need the names as such: alex | sean | ashley.

What do you guys think?

---------- Post updated at 11:35 AM ---------- Previous update was at 10:51 AM ----------

also guys, this is what i had so far. i know it's wrong (especially the * part, it doesn't work) but like i said i am very new to this. i was trying to do this for one user first but i actually want to do multiple like i mentioned.

Code:
#!/bin/sh

echo "Enter login name and password"
read trythis

if [ $trythis = "Aarin_dtfc" ]
then
	echo "You are logged in!"
else [ $trythis = "Aarin_*" ]
	echo "Wrong password!"
	exit 1
else [ $trythis = "*_dtfc" ]
	echo "Login name is not recognized!"
	exit 2
fi
exit 0



---------- Post updated at 02:02 PM ---------- Previous update was at 11:35 AM ----------

ok i rewrote the code to this:

Code:
#!/bin/sh
echo "Enter username"
read username
if [ $username = "Aarin" ]
then  
 echo Enter password
 read password
case $username in
 Aarin ) pass=dtfc;;
 Rick ) pass=unpo
esac
while [ "$password" != "$pass" ]; do
 echo "Wrong password!"
 return 1
done
echo "You are logged in!" 
return 0
else
 echo "Login name not recognized"
fi
return 2

the only thing i am having trouble doing is adding multiple usernames to the if statement
Last edited by pludi; 02-25-2010 at 04:17 PM.. Reason: Please use code tags.......
 

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LEARN ABOUT PHP

ldap_compare

LDAP_COMPARE(3) 							 1							   LDAP_COMPARE(3)

ldap_compare - Compare value of attribute found in entry specified with DN

SYNOPSIS

       mixed ldap_compare (resource  $link_identifier, string  $dn, string  $attribute, string	$value)

DESCRIPTION

	Compare $value of $attribute with value of same attribute in an LDAP directory entry.

PARAMETERS

	      o $link_identifier
		- An LDAP link identifier, returned by ldap_connect(3).

	      o $dn
		- The distinguished name of an LDAP entity.

	      o $attribute
		- The attribute name.

	      o $value
		- The compared value.

RETURN VALUES

	Returns TRUE if $value matches otherwise returns FALSE. Returns -1 on error.

EXAMPLES

	The following example demonstrates how to check whether or not given password matches the one defined in DN specified entry.

       Example #1

	      Complete example of password check

	      <?php

	      $ds=ldap_connect("localhost");  // assuming the LDAP server is on this host

	      if ($ds) {

		  // bind
		  if (ldap_bind($ds)) {

		      // prepare data
		      $dn = "cn=Matti Meikku, ou=My Unit, o=My Company, c=FI";
		      $value = "secretpassword";
		      $attr = "password";

		      // compare value
		      $r=ldap_compare($ds, $dn, $attr, $value);

		      if ($r === -1) {
			  echo "Error: " . ldap_error($ds);
		      } elseif ($r === true) {
			  echo "Password correct.";
		      } elseif ($r === false) {
			  echo "Wrong guess! Password incorrect.";
		      }

		  } else {
		      echo "Unable to bind to LDAP server.";
		  }

		  ldap_close($ds);

	      } else {
		  echo "Unable to connect to LDAP server.";
	      }
	      ?>

NOTES

       Warning

	      ldap_compare(3) can NOT be used to compare BINARY values!

PHP Documentation Group 													   LDAP_COMPARE(3)
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