Sponsored Content
Top Forums Shell Programming and Scripting bash case statement output help Post 302393337 by Scrutinizer on Monday 8th of February 2010 12:47:40 PM
Old 02-08-2010
Hi, try:

Code:
while read LINE
do
  case "$LINE" in 
      a*) echo ${FOO[*]}
          unset FOO
          FOO[0]="$LINE";;
       *) FOO[$[${#FOO[@]}+1]]="$LINE";;
  esac
done < output.txt
echo ${FOO[*]}

-or-
Code:
while read LINE
do
  case "$LINE" in
      a*) printf "\n"
  esac
  printf "%s" "$LINE"
done < output.txt
printf "\n"


Last edited by Scrutinizer; 02-08-2010 at 01:56 PM..
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

case statement

hi all i'm writing a script and in it i need to prompt the user if the entered value is correct or not ,i wrote the following and its not working ,its executing the script even if i enter Y/N pls any help is appreciated echo "\nAre you sure you entered the right Destination Environment? y :... (5 Replies)
Discussion started by: bkan77
5 Replies

2. UNIX for Dummies Questions & Answers

If or Case Statement

I want to write a program with the following variables: a=7000 b=24000 c=613.8 The user can enter two words: Vivid or Blue for example. The challenge is that the user might not want to write the words the way they appear. The user can write V or v or vivid or Vivid or write Blue or blue, or B,... (1 Reply)
Discussion started by: Ernst
1 Replies

3. Shell Programming and Scripting

help with case statement

I am writing a script to pull diskspace information from our servers. Here is the script that I wrote: #!/bin/ksh for host in `cat /oper/hosts/esc.misc` do ssh -q -o ConnectTimeout=10 operator@$host df -h|grep "/dev/" |egrep '8%|9%|100%' | awk '{print H " " "at " $5 " with " $4 "... (1 Reply)
Discussion started by: rkruck
1 Replies

4. Shell Programming and Scripting

[BASH] recognise new line regex in case statement

Hi, I'm trying to write a routine to parse a file that contains data that will be read into arrays. The file is composed of labels to identify data types and arbitrary lines of data with the usual remarks and empty new lines as is common with config files. The initial pass is built as so:... (3 Replies)
Discussion started by: ASGR
3 Replies

5. Shell Programming and Scripting

Can you use logical operators in a case statement (bash)?

I'm pretty sure I already know the answer to this, but I want to make sure I'm not overlooking anything. I'm working on a log monitoring script and every 10 lines I want to display a summary of events. The thing is, there are a lot of possible events, that likely won't have happened, so I only want... (0 Replies)
Discussion started by: DeCoTwc
0 Replies

6. Shell Programming and Scripting

Problem using bash case statement

I have the following bash script and it is not accepting the lines "--"|"--""-") "--""-"") while do echo "Current Argument is ${1}" case "$1" in "--"|"--""-") echo "Argument is ${1}" shift # Skip ahead one to the next argument. ... (1 Reply)
Discussion started by: kristinu
1 Replies

7. Shell Programming and Scripting

Bash case Statement and Using Line Anchors?

Hello All, I am writing a script that is to be placed on multiple servers, and of course I've started running into some compatibility issues for certain shell commands. The code below worked just fine on most of my machines except for a couple. Here I had 4 separate lines in my script that... (3 Replies)
Discussion started by: mrm5102
3 Replies

8. UNIX for Dummies Questions & Answers

Case statement help

Hi I am new to shell scripting, I wanted to make a shell script that has a case statement asking the user to select their city 1)london 2)tokyo 3) etc., I then want the users input to be stored in a variable and echoed out in another script; so for example if the user selects tokyo, tokyo city code... (2 Replies)
Discussion started by: scriptnewbie
2 Replies

9. Shell Programming and Scripting

BASH - case statement

Hi Gurus, I have the below BASH code which does not works for upper case alphabets except Z (upper case Z). What may be the reason. Also escape sequences like \n, \t, \b, \033(1m \033(0m (For bold letter) are not working. case $var in ) echo "Lower case alphabet" ;; ... (7 Replies)
Discussion started by: GaneshAnanth
7 Replies

10. Shell Programming and Scripting

Bash read input in case statement not working as expected

I'm having an issue with bash read input when using a case statement. The script halts and doesn't read the input on the first loop. if I hit enter then the scripts starts to respond as expected. Need some help here. defaultans=8hrs read -e -i $defaultans -p "${bldwht}How long would you like... (5 Replies)
Discussion started by: woodson2
5 Replies
Symbol(3pm)						 Perl Programmers Reference Guide					       Symbol(3pm)

NAME
Symbol - manipulate Perl symbols and their names SYNOPSIS
use Symbol; $sym = gensym; open($sym, "filename"); $_ = <$sym>; # etc. ungensym $sym; # no effect # replace *FOO{IO} handle but not $FOO, %FOO, etc. *FOO = geniosym; print qualify("x"), " "; # "Test::x" print qualify("x", "FOO"), " " # "FOO::x" print qualify("BAR::x"), " "; # "BAR::x" print qualify("BAR::x", "FOO"), " "; # "BAR::x" print qualify("STDOUT", "FOO"), " "; # "main::STDOUT" (global) print qualify(*x), " "; # returns *x print qualify(*x, "FOO"), " "; # returns *x use strict refs; print { qualify_to_ref $fh } "foo! "; $ref = qualify_to_ref $name, $pkg; use Symbol qw(delete_package); delete_package('Foo::Bar'); print "deleted " unless exists $Foo::{'Bar::'}; DESCRIPTION
"Symbol::gensym" creates an anonymous glob and returns a reference to it. Such a glob reference can be used as a file or directory handle. For backward compatibility with older implementations that didn't support anonymous globs, "Symbol::ungensym" is also provided. But it doesn't do anything. "Symbol::geniosym" creates an anonymous IO handle. This can be assigned into an existing glob without affecting the non-IO portions of the glob. "Symbol::qualify" turns unqualified symbol names into qualified variable names (e.g. "myvar" -> "MyPackage::myvar"). If it is given a sec- ond parameter, "qualify" uses it as the default package; otherwise, it uses the package of its caller. Regardless, global variable names (e.g. "STDOUT", "ENV", "SIG") are always qualified with "main::". Qualification applies only to symbol names (strings). References are left unchanged under the assumption that they are glob references, which are qualified by their nature. "Symbol::qualify_to_ref" is just like "Symbol::qualify" except that it returns a glob ref rather than a symbol name, so you can use the result even if "use strict 'refs'" is in effect. "Symbol::delete_package" wipes out a whole package namespace. Note this routine is not exported by default--you may want to import it explicitly. perl v5.8.0 2002-06-01 Symbol(3pm)
All times are GMT -4. The time now is 09:30 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy