Sponsored Content
Top Forums Shell Programming and Scripting bash - Variable made of variable Post 302392834 by jolecanard on Friday 5th of February 2010 04:12:10 PM
Old 02-05-2010
Quote:
Originally Posted by scottn
By using "eval echo ..."?
I could not get anything working...
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

passing variable from bash to perl from bash script

Hi All, I need to pass a variable to perl script from bash script, where in perl i am using if condition. Here is the cmd what i am using in perl FROM_DATE="06/05/2008" TO_DATE="07/05/2008" "perl -ne ' print if ( $_ >="$FROM_DATE" && $_ <= "$TO_DATE" ) ' filename" filename has... (10 Replies)
Discussion started by: arsidh
10 Replies

2. Shell Programming and Scripting

bash and ksh: variable lost in loop in bash?

Hi, I use AIX (ksh) and Linux (bash) servers. I'm trying to do scripts to will run in both ksh and bash, and most of the time it works. But this time I don't get it in bash (I'm more familar in ksh). The goal of my script if to read a "config file" (like "ini" file), and make various report.... (2 Replies)
Discussion started by: estienne
2 Replies

3. Shell Programming and Scripting

BASH get variable according to name of another variable

Just started BASH scripting, and I tried to make a script 'args' to display all of the arguments that I give to it. #!/bin/bash if then echo "No arguments specified." fi val= for ((i=1; i <= $# ; i++)) do eval "\$val=\$$i" echo "Argument number $i is $var." done However... (3 Replies)
Discussion started by: test_test
3 Replies

4. Shell Programming and Scripting

Using the value of one variable to name another variable (in bash)

Hello all, I'm working on a script, and as part of it, I'm trying to create a loop that will run through a stored piece of information a certain number of times pulling out information, and each time create a variable with a unique name that will store that information. I'm sure it's a simple... (3 Replies)
Discussion started by: DeCoTwc
3 Replies

5. Shell Programming and Scripting

[Bash]variable does not keep its value

Hello all, I have this shell script, but do not understand why the variables inside the if block does not keep its value outside. Is it because of the pipe ? How can i fix this problem ? Thank you for helping. local alarm="" local num_alarm=0 local -a alarms ... (3 Replies)
Discussion started by: trickstar
3 Replies

6. Shell Programming and Scripting

How to define a variable with variable definition is stored in a variable?

Hi all, I have a variable say var1 (output from somewhere, which I can't change)which store something like this: echo $var1 name=fred age=25 address="123 abc" password=pass1234 how can I make the variable $name, $age, $address and $password contain the info? I mean do this in a... (1 Reply)
Discussion started by: freddy1228
1 Replies

7. Shell Programming and Scripting

Use variable in bash

$ p="1 2 5 8" $ set -- $p $ echo $3 5 $ k=3 $ echo \$${k} $3 I want the "echo \$${k}" to get the output 5 , how to modify ? (6 Replies)
Discussion started by: yanglei_fage
6 Replies

8. Shell Programming and Scripting

Variable in bash help

#aa=xxxx #zz="cc $aa" #aa=gggg #echo $zz out put is cc xxxx if I want to get cc gggg how should I do, I don't want to write zz="c $aa " after aa=gggg (2 Replies)
Discussion started by: yanglei_fage
2 Replies

9. Shell Programming and Scripting

Bash variable within variable

Hello, Can I ask how to expand variable that contains another in bash? I need to loop variable within another one like this: RD1=testgrp RD2=testgroup RD3=testgroupfile RD4=tstgroup ... RD40=try2013 DEST=/home/king/finaldir for i in {1..40}; do mv ${RD${i}} ${DEST} done I do not... (8 Replies)
Discussion started by: yifangt
8 Replies

10. Shell Programming and Scripting

Using RegEx with variable within bash if [[ ]]

I stumbled upon a problem, which I simplified to this: There is a list of numbers, stored in variable $LIST, lets use `seq 5 25` for demonstration. There is a number that should be compared against this list. For demonstration I use user input - read VALUE I am trying to compare RegEx... (2 Replies)
Discussion started by: Zorbeg
2 Replies
SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
All times are GMT -4. The time now is 10:58 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy