02-05-2010
Quote:
Originally Posted by
scottn
By using "eval echo ..."?
I could not get anything working...
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1. Shell Programming and Scripting
Hi All,
I need to pass a variable to perl script from bash script, where in perl i am using if condition. Here is the cmd what i am using in perl
FROM_DATE="06/05/2008"
TO_DATE="07/05/2008"
"perl -ne ' print if ( $_ >="$FROM_DATE" && $_ <= "$TO_DATE" ) ' filename"
filename has... (10 Replies)
Discussion started by: arsidh
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2. Shell Programming and Scripting
Hi,
I use AIX (ksh) and Linux (bash) servers. I'm trying to do scripts to will run in both ksh and bash, and most of the time it works. But this time I don't get it in bash (I'm more familar in ksh).
The goal of my script if to read a "config file" (like "ini" file), and make various report.... (2 Replies)
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3. Shell Programming and Scripting
Just started BASH scripting, and I tried to make a script 'args' to display all of the arguments that I give to it.
#!/bin/bash
if
then
echo "No arguments specified."
fi
val=
for ((i=1; i <= $# ; i++))
do
eval "\$val=\$$i"
echo "Argument number $i is $var."
done
However... (3 Replies)
Discussion started by: test_test
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4. Shell Programming and Scripting
Hello all,
I'm working on a script, and as part of it, I'm trying to create a loop that will run through a stored piece of information a certain number of times pulling out information, and each time create a variable with a unique name that will store that information. I'm sure it's a simple... (3 Replies)
Discussion started by: DeCoTwc
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5. Shell Programming and Scripting
Hello all,
I have this shell script, but do not understand why the variables inside the if block does not keep its value outside. Is it because of the pipe ? How can i fix this problem ?
Thank you for helping.
local alarm=""
local num_alarm=0
local -a alarms
... (3 Replies)
Discussion started by: trickstar
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6. Shell Programming and Scripting
Hi all,
I have a variable say var1 (output from somewhere, which I can't change)which store something like this:
echo $var1
name=fred
age=25
address="123 abc"
password=pass1234
how can I make the variable $name, $age, $address and $password contain the info?
I mean do this in a... (1 Reply)
Discussion started by: freddy1228
1 Replies
7. Shell Programming and Scripting
$ p="1 2 5 8"
$ set -- $p
$ echo $3
5
$ k=3
$ echo \$${k}
$3
I want the "echo \$${k}" to get the output 5 , how to modify ? (6 Replies)
Discussion started by: yanglei_fage
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8. Shell Programming and Scripting
#aa=xxxx
#zz="cc $aa"
#aa=gggg
#echo $zz
out put is
cc xxxx
if I want to get
cc gggg
how should I do, I don't want to write zz="c $aa " after aa=gggg (2 Replies)
Discussion started by: yanglei_fage
2 Replies
9. Shell Programming and Scripting
Hello,
Can I ask how to expand variable that contains another in bash? I need to loop variable within another one like this:
RD1=testgrp
RD2=testgroup
RD3=testgroupfile
RD4=tstgroup
...
RD40=try2013
DEST=/home/king/finaldir
for i in {1..40}; do
mv ${RD${i}} ${DEST}
done
I do not... (8 Replies)
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10. Shell Programming and Scripting
I stumbled upon a problem, which I simplified to this:
There is a list of numbers, stored in variable $LIST, lets use `seq 5 25` for demonstration.
There is a number that should be compared against this list. For demonstration I use user input - read VALUE
I am trying to compare RegEx... (2 Replies)
Discussion started by: Zorbeg
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LEARN ABOUT DEBIAN
shell-quote
SHELL-QUOTE(1p) User Contributed Perl Documentation SHELL-QUOTE(1p)
NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS
--debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)