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Full Discussion: one liner to extract path from PATH variable
Top Forums Shell Programming and Scripting one liner to extract path from PATH variable Post 302392575 by Scrutinizer on Thursday 4th of February 2010 10:18:47 PM
Old 02-04-2010
If you have grep -o:
Code:
echo "$PATH"|grep -o "[^:]*java[^:]*"

-or-
Code:
echo "$PATH"|awk /java/ RS=":"

Last edited by Scrutinizer; 02-04-2010 at 11:24 PM..
 

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LEARN ABOUT ULTRIX

zgrep

ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME

       zgrep - search possibly compressed files for a regular expression

SYNOPSIS

       zgrep [ grep_options ] [ -e ] pattern filename...

DESCRIPTION

       Zgrep  invokes  grep  on  compressed  or  gzipped  files.   These  grep	options  will  cause  zgrep  to  terminate  with  an  error  code:
       (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*).  All other options specified are passed directly to grep.  If no file is specified,  then  the
       standard input is decompressed if necessary and fed to grep.  Otherwise the given files are uncompressed if necessary and fed to grep.

       If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.

EXIT CODE

       2 - An option that is not supported was specified.

AUTHOR

       Charles Levert (charles@comm.polymtl.ca)

SEE ALSO

       grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)

																	  ZGREP(1)
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