Hi,
I have a simple for loop, given below,thats giving me trouble. I am new to shell scripting and I don't know what I am missing. I appreciate your help.
a=1
b=5
for(a=1;a<=b;a++)
[/CODE]
First, that is not standard shell syntax for a loop.
The syntax is:
Some shells have a non-standard extension, which is probably what you want:
Quote:
That will print a literal 'a'; to reference a variable, precede it with a dollar sign:
hi all,
i have written the following code:
while(proceed !='Y' && proceed!='N' && proceed!='y' && proceed!='n')
{
printf("\nPress \n\t 'Y' or 'y' to continue \n\t 'N' or 'n' to cancel:");
scanf("%c",&proceed);
}
the output i am gettin is:
Press
'Y' to continue
... (1 Reply)
Hi,
I have a directory called logs in which i have the log files.
i have to touch the file before deleting it.
i am doing like this
filestodelete="*.log* *log*"
for files in $filestodelete
do
touch $files $files.$(date +%a)
rm -f $filestodelete
done
touch is not working... (5 Replies)
Hi guys my while do loop is not working properly;
As soon as the load_date and run_date is same it should stop can somebody tell me where I am having the problem?
In an oracle table I have
LOAD_DT=5/1/2009 DATE datatype
RUN_DT=5/5/2009 DATE datatype
Now in a script with a spool file I get the... (15 Replies)
Hi Guys,
This is my code.. I am getting an error in the inside while statement when comparing.. I am not able to figure it out.. Pls help me...
while read value fatherid son_id top_id r_type
do
inside_value=1;
echo $inside_value;
echo $r_type;
while
do
echo... (6 Replies)
hi
I had created a while loop in a script file called whiletest.sh as follows
as follows:
count=0
max=10
while
do
echo $count
echo count=$(count+1)" "
done
echo "value of count:$count"
then i run the script with the command
sh whilestest.sh
but its giving me an error... (5 Replies)
I have a while loop with -f and -o option.Can any one please tell me what that stands for?The Sample code is as follows:-
while
do
## some processing
done (10 Replies)
Hi Script Gurus,
I am facing issue with while loop in bash. The while loop is running as end less loop even after given criteria does not meet.
STATE_BEFORE_SPLIT () {
for clone in $Clonegroups; do
state=$( $Navicmd -listclone -name $clone -cloneid $Cloneid |awk... (3 Replies)
Hi,
I work on Ab-initio ETL tool which is based on Unix. I made a small script which has two loop's one with in another. All the functionality is working for the first line of outer loop but when it comes to other lines of outer loop it is throwing error as command not found. Below is the... (4 Replies)
I am trying to do a while do loop that asks for a password and returns if the password entered is incorrect. I have that part working however i want to modify it so that if a similar word is entered it will read "that is close but incorrect" and i cannot seem to get it working, being new in the... (6 Replies)
Hi all,
a problem with a loop. Imagine it starts with
var1="$(cat txtif.out )"while
do
echo file1
echo file2
echo y > txtif.out
if
then
break
fi
done
exit 0
the problem is that if the file is changing during the loop seems to continue as it reads "x" state,... (5 Replies)
Discussion started by: Board27
5 Replies
LEARN ABOUT CENTOS
shell-quote
SHELL-QUOTE(1) User Contributed Perl Documentation SHELL-QUOTE(1)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.16.3 2010-06-11 SHELL-QUOTE(1)