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Top Forums Shell Programming and Scripting Need 10 lines before the first occurance of a pattern Post 302390167 by Franklin52 on Wednesday 27th of January 2010 05:04:24 AM
Old 01-27-2010
If your grep version don't support the -B option, this should do the job:

Code:
awk '
/check/ {
  for(i=0;i<10;i++) {
    print a[(NR+i)%10]
  }
  exit
}
{a[NR%10]=$0}
' file

 

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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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