Hi !!
How do u run three scripts one after another automatically using crontab command at some specified regular interval.
Say i have three scripts A,B,C and i want to run the three scripts A followed by B followed by C.
REQUIRE HELP URGENTLY
Thanks in advance
Arunava
. (3 Replies)
Hi all... I have several scripts of varying types (shell script, expect script, awk script) that I would like to run within 1 script.. They also take a command line argument (which it is getting successfully). The problem is, the parent script is exiting after the first script it calls is... (2 Replies)
I haven't been on a unix system in a long time and I'm trying to teach a friend unix. After looking at/testing various options cygwin seemed to be the easiest to download and install.
Everything works pretty much as I recall and I even tested a small java program on it.
I can't seem to get... (4 Replies)
Hello folks,
I've got this script which connects to different boxes and executes a certain script in those locations. The following is the line from where i am trying to do this:
(sleep 1; echo $USERID ; sleep 1; echo $PASSWD ; sleep 1 ; echo y ; sleep 1 ; echo "\r" ; sleep 1 ; echo "cd... (1 Reply)
Looking for a logic where say i have a script called parent_script which is used to call other 4 to 5 child scripts in background as..
cat parent_script # containing 65 lines
1
2
..
35 while read child_script
36 do
37 ./child_script_name&
38 done< ${SCRIPT_LISTS}
39
40 # Need to have... (2 Replies)
I am from MQ/MB technology. My requirement is to display the queue manger and broker status on daily basis.
If I manually run the script, it works fine and displays output. But when I have scheduled the same using cronjobs it shows only the queue manger status and not the broker status.
Can... (3 Replies)
Assume I want to run a sequence of scripts:
script0001.sh
script0002.sh
script0003.sh
...
script0122.sh
script0123.sh
I only know a little Linux scripting, so the following is the best I can write
for k in $(seq 1 123)
do
./script${k}.sh
done
Of course it doesn't work... (2 Replies)
Hi ,
Can someone help!
I need a shell script to run multiple scripts by using single shell script,
incase any one of the scripts fails, it should get exit and after trouble shooting if we re-execute it, it should start from the failed script (4 Replies)
Discussion started by: anniesurolyn
4 Replies
LEARN ABOUT DEBIAN
filetest
filetest(3perl) Perl Programmers Reference Guide filetest(3perl)NAME
filetest - Perl pragma to control the filetest permission operators
SYNOPSIS
$can_perhaps_read = -r "file"; # use the mode bits
{
use filetest 'access'; # intuit harder
$can_really_read = -r "file";
}
$can_perhaps_read = -r "file"; # use the mode bits again
DESCRIPTION
This pragma tells the compiler to change the behaviour of the filetest permission operators, "-r" "-w" "-x" "-R" "-W" "-X" (see perlfunc).
The default behaviour of file test operators is to use the simple mode bits as returned by the stat() family of system calls. However,
many operating systems have additional features to define more complex access rights, for example ACLs (Access Control Lists). For such
environments, "use filetest" may help the permission operators to return results more consistent with other tools.
The "use filetest" or "no filetest" statements affect file tests defined in their block, up to the end of the closest enclosing block (they
are lexically block-scoped).
Currently, only the "access" sub-pragma is implemented. It enables (or disables) the use of access() when available, that is, on most UNIX
systems and other POSIX environments. See details below.
Consider this carefully
The stat() mode bits are probably right for most of the files and directories found on your system, because few people want to use the
additional features offered by access(). But you may encounter surprises if your program runs on a system that uses ACLs, since the stat()
information won't reflect the actual permissions.
There may be a slight performance decrease in the filetest operations when the filetest pragma is in effect, because checking bits is very
cheap.
Also, note that using the file tests for security purposes is a lost cause from the start: there is a window open for race conditions (who
is to say that the permissions will not change between the test and the real operation?). Therefore if you are serious about security,
just try the real operation and test for its success - think in terms of atomic operations. Filetests are more useful for filesystem
administrative tasks, when you have no need for the content of the elements on disk.
The "access" sub-pragma
UNIX and POSIX systems provide an abstract access() operating system call, which should be used to query the read, write, and execute
rights. This function hides various distinct approaches in additional operating system specific security features, like Access Control
Lists (ACLs)
The extended filetest functionality is used by Perl only when the argument of the operators is a filename, not when it is a filehandle.
Limitation with regard to "_"
Because access() does not invoke stat() (at least not in a way visible to Perl), the stat result cache "_" is not set. This means that the
outcome of the following two tests is different. The first has the stat bits of "/etc/passwd" in "_", and in the second case this still
contains the bits of "/etc".
{ -d '/etc';
-w '/etc/passwd';
print -f _ ? 'Yes' : 'No'; # Yes
}
{ use filetest 'access';
-d '/etc';
-w '/etc/passwd';
print -f _ ? 'Yes' : 'No'; # No
}
Of course, unless your OS does not implement access(), in which case the pragma is simply ignored. Best not to use "_" at all in a file
where the filetest pragma is active!
As a side effect, as "_" doesn't work, stacked filetest operators ("-f -w $file") won't work either.
This limitation might be removed in a future version of perl.
perl v5.14.2 2010-12-30 filetest(3perl)