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Top Forums Shell Programming and Scripting Need script to select multiple files from archive directory based on the date range Post 302388923 by rdcwayx on Friday 22nd of January 2010 12:45:18 AM
Old 01-22-2010
Code:
Not tested:

#! /usr/bin/bash

BASE=/projects/home01/archive
DEST=/tmp

for file in `find $BASE -type f -name "*.txt"`
do
   date=$(echo $FILE|awk -F[\/_] '{print $(NF-1)}')
   if [ "$date" > "$1" && "$date" < "$2" ] ; then 
       mv $file $DEST/$file
   fi
done

 

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DATETIME.FORMAT(3)							 1							DATETIME.FORMAT(3)

DateTime::format - Returns date formatted according to given format

       Object oriented style

SYNOPSIS
public string DateTime::format (string $format) DESCRIPTION
string DateTimeImmutable::format (string $format) string DateTimeInterface::format (string $format) Procedural style string date_format (DateTimeInterface $object, string $format) Returns date formatted according to given format. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3) o $format - Format accepted by date(3). RETURN VALUES
Returns the formatted date string on success or FALSE on failure. EXAMPLES
Example #1 DateTime.format(3) example Object oriented style <?php $date = new DateTime('2000-01-01'); echo $date->format('Y-m-d H:i:s'); ?> Procedural style <?php $date = date_create('2000-01-01'); echo date_format($date, 'Y-m-d H:i:s'); ?> The above example will output: 2000-01-01 00:00:00 NOTES
This method does not use locales. All output is in English. SEE ALSO
date(3). PHP Documentation Group DATETIME.FORMAT(3)
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