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Full Discussion: 2 listeners in a port
Top Forums Shell Programming and Scripting 2 listeners in a port Post 302387211 by fif14344 on Friday 15th of January 2010 01:09:18 AM
Old 01-15-2010
Hi.
Yes it is a TCP server. But it is listening to a port. port 17477. hmm... then it is not possible then huh..
Even though if the other one is like trying to catch the request only? i mean like ex.
If a request to that specific port 17477 was sent from a client the program will record that request but will not return anything while the other program will also recieve that request and will return something. Can it be done?
 

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XvUngrabPort(3) 						  libXv Functions						   XvUngrabPort(3)

NAME
XvUngrabPort - release port grabbed for video operation SYNOPSIS
#include <X11/extensions/Xvlib.h> int XvUngrabPort(Display *dpy, XvPortID port, Time time); ARGUMENTS
dpy Specifies the connection to the X server. port Specifies the port to be released. If the port had not been previously grabbed, the request is ignored. time Specifies the request timestamp. DESCRIPTION
XvUngrabPort(3) releases a grabbed port. If time specifies a time before the last XvGrabPort(3) was executed, the request is ignored. RETURN VALUES
[Success] Returned if XvUngrabPort(3) completed successfully. [XvBadExtension] Returned if the Xv extension is unavailable. [XvBadAlloc] Returned if XvUngrabPort(3) failed to allocate memory to process the request. DIAGNOSTICS
[XvBadPort] Generated if the requested port does not exist. SEE ALSO
XvGrabPort(3) X Version 11 libXv 1.0.7 XvUngrabPort(3)
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