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Top Forums UNIX for Dummies Questions & Answers Understanding the output command Post 302386816 by Corona688 on Wednesday 13th of January 2010 04:54:30 PM
Old 01-13-2010
Quote:
Originally Posted by Ariean
I am missing something what do u mean by standard error? i understand standard output is the output printed on screen when i execute the script. But i didn't understand "2>&1" part, whats happening over there?

Thanks,
Ariean
By tradition, a UNIX process has three default streams: standard input(stdin), standard output(stdout), and standard error(stderr). stdin is represents the terminal keyboard as file descriptor 0, stdout represents the terminal screen as file descriptor 1, and stderr is also directed to the terminal screen as file descriptor 2.

The idea with having two files going to the terminal is to keep data and error messages separate. You can redirect the data output of a process into a file and still see human-readable error messages on your terminal. It also helps keep error messages OUT of data files since other programs probably won't need or understand them.

Here they're redirecting both stdout and stderr into the data file, for better or for worse. The "2>&1" bit tells it to redirect FD 2, stderr, to the same destination as FD 1, stdout.
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bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
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