I have a habit of using curly braces around my variables to explicity state when the name of a variable starts and ends. Here's one example where it would be needed:
Also without directing it to /dev/null, the output would show on the screen. Although your script would work, the end user doesn't really need to see this output. It was only done to test whether the permission was present, so we just needed "$?" that contained the success/failure code of that command.
Let me know if this helps or if you have any other questions.
Hi,
I'm trying to execute a shell script from application (Informatica). The script works fine when I execute it from command line but fails when executed from Informatica. The tricky part is that there is other scripts in the same folder that can be executed succesfully from both command line... (1 Reply)
Hi
I have this code, and i want work with a ls -shalR output in .txt
What i need read to do this??
Where start?
#!/usr/bin/perl
# Allrights- A perl tool for making backups of file permissions
# Copyright (C) 2005 Norbert Klein <norbert@acodedb.com>
# This program is free... (1 Reply)
Hi All,
I have a shell script which we keep on changing permissions on a On-Demand Basis-->for e:g--from 400(Read only) to 740(Execute permission) etc.
Is there any way by which I can view the history of the script?-->I am interested in finding out the date-time stamps when the script's... (2 Replies)
Hi all,
I am using a batch script that ftps the compressed xml files to the Unix environment from the Windows environment and i perform this using the below line of coding:
echo cd %VAR_TR_FTP_DIR% > %TR_FTP_BATCH_FILE BatchNum%
Echo lcd "%VAR_TR_SOURCE_PATH_BatchNum%">> %TR_FTP_BATCH_FILE... (1 Reply)
hello,
I have to write a script to run the other script inside it.So iam planning to write like this?
first check the perimissions of the file.
Alogorthim
----------
if(!filepermissions == execute)
then
echo" Permissions denined"
else
execute the script.
file name is : load_mf.sh... (1 Reply)
I have a script were I issue the following command:
perl -p -i -e "s/$v31a/$db2/" $dbn31
My script fails with permission error. However, at the command line I can edit the directory in question. I am using uname 002 in my script. So, why can i update manually but not in a script? (10 Replies)
Hi
I have written the following script that later I want to put in cron,:
#!/bin/bash
_find="/usr/bin/find"
_paths="/moneta_polled01/mediation_gsm /moneta_polled01/mediation_mmsc"
for d in $_paths
do
$_find $d -type f -exec chmod 777 {} \;
done
but it does not seem to be... (8 Replies)
Hi All
I have the following script that is supposed to change permissions of incoming files to a directory, but it does not seem to do what I want, please can you help:
mkdir -p /tmp/tmpdir
find /moneta_polled01/sgsn/ -exec ls -l {} \; |grep -v rwxrwxrwx |awk '{print $9}' >... (4 Replies)
Hello,
I'm pretty new to scripting and trying to do a simple (well, I thought so) administrator task. I'm using bash.
I want to create 10 directories under the one directory and apply permissions at the same time.
I've worked out the make directories part: mkdir /userdata/folder{1..50}... (7 Replies)
Discussion started by: jimothy007
7 Replies
LEARN ABOUT SUSE
cal
CAL(1) BSD General Commands Manual CAL(1)NAME
cal -- displays a calendar
SYNOPSIS
cal [-smjy13] [[[day] month] year]
DESCRIPTION
Cal displays a simple calendar. If arguments are not specified, the current month is displayed. The options are as follows:
-1 Display single month output. (This is the default.)
-3 Display prev/current/next month output.
-s Display Sunday as the first day of the week.
-m Display Monday as the first day of the week.
-j Display Julian dates (days one-based, numbered from January 1).
-y Display a calendar for the current year.
-V Display version information and exit.
A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: ``cal 89'' will not display a calen-
dar for 1989. Two parameters denote the month (1 - 12) and year. Three parameters denote the day (1-31), month and year, and the day will
be highlighted if the calendar is displayed on a terminal. If no parameters are specified, the current month's calendar is displayed.
A year starts on Jan 1. The first day of the week is determined by the locale.
The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September. By this time, most countries had recognized the ref-
ormation (although a few did not recognize it until the early 1900's.) Ten days following that date were eliminated by the reformation, so
the calendar for that month is a bit unusual.
HISTORY
A cal command appeared in Version 6 AT&T UNIX.
OTHER VERSIONS
Several much more elaborate versions of this program exist, with support for colors, holidays, birthdays, reminders and appointments, etc.
For example, try the cal from http://home.sprynet.com/~cbagwell/projects.html or GNU gcal.
AVAILABILITY
The cal command is part of the util-linux-ng package and is available from ftp://ftp.kernel.org/pub/linux/utils/util-linux-ng/.
BSD June 6, 1993 BSD