I need to increment a date value through shell script.
Input value consist of start date and end date in DATE format of unix.
For eg.
I need increment a date value of 1/1/09 to 31/12/09 i.e for a whole yr.
The output must look like
1/1/09
2/2/09
.
.
.
31/1/09
.
.
1/2/09
.
28/2/09... (1 Reply)
Hi,
Iam new to scripting language.:o
can someone help me out solving this thread?hopingly ya....:)
I want to write a script which connects to db and searches the count in a table which has date column and id column.
If the count is not equal to 0 then it should increment the date with the one... (4 Replies)
Hi,
I have a variable lets say DATA_DATE.
I have to pass some value to this variable in YYYYMMDD format.
lets say today I have passed this variable as :
DATA_DATE=20100107
Then pls help me how to calculate another variable DATA_DATE1 (which is DATA_DATE+1).
The code should work... (3 Replies)
hi Friends,
Today_Dt=`date "+%Y-%m-%d"`
So the Today date is 2010-05-03
I have a file which has date values as below
2010-04-27
2010-04-02
2010-04-18
2010-04-28
2010-04-29
.. (1 Reply)
hi experts,
my requirement is like this i need to develop a shell script to update date part with new incremental date time in file some 'X' which is kept at some server location incrementing every two hours.as i am new to this scripting i need support from u people,thanx in advance (1 Reply)
Hi All,
I have a file which has hundred of records with fixed number of fields. In each record there is set of 8 characters which represent the duration of that activity. I want to sum up the duration present in all the records for a report. The problem is the duration changes per record so I... (5 Replies)
hey guys,
I need to incerement the date variable for instance
echo `date '+%F %H:%M:00'`
this produces
2014-08-02 20:05:00
-I will grant this to : $Datehour and need to assign 1 hr from now to $Datelasthour
-the script time will be used to talk to DB system information.
however... (4 Replies)
Hi,
I have parameter file wo_location.prm which has a date variable $last_upd_date= 02032016.
I need to write a unix shell script to find that variable and increment it by 1 day.
The path to the file is root/dir_lc/shared/param/wo_location.prm and the variable is $last_upd_date.
Any... (2 Replies)
Discussion started by: isenhiem
2 Replies
LEARN ABOUT REDHAT
gendiff
GENDIFF(1) General Commands Manual GENDIFF(1)NAME
gendiff - utility to aid in error-free diff file generation
SYNOPSIS
gendiff <directory> <diff-extension>
DESCRIPTION
gendiff is a rather simple script which aids in generating a diff file from a single directory. It takes a directory name and a "diff-
extension" as its only arguments. The diff extension should be a unique sequence of characters added to the end of all original, unmodi-
fied files. The output of the program is a diff file which may be applied with the patch program to recreate the changes.
The usual sequence of events for creating a diff is to create two identical directories, make changes in one directory, and then use the
diff utility to create a list of differences between the two. Using gendiff eliminates the need for the extra, original and unmodified
directory copy. Instead, only the individual files that are modified need to be saved.
Before editing a file, copy the file, appending the extension you have chosen to the filename. I.e. if you were going to edit somefile.cpp
and have chosen the extension "fix", copy it to somefile.cpp.fix before editing it. Then edit the first copy (somefile.cpp).
After editing all the files you need to edit in this fashion, enter the directory one level above where your source code resides, and then
type
$ gendiff somedirectory .fix > mydiff-fix.patch
You should redirect the output to a file (as illustrated) unless you want to see the results on stdout.
SEE ALSO diff(1), patch(1)AUTHOR
Marc Ewing <marc@redhat.com>
4th Berkeley Distribution Mon Jan 10 2000 GENDIFF(1)