I know in vi you can do
:%s/replaceme/withthis/
but if i want to find all lines say without a # at the begining and I want to put it in how would that command be formatted? I can't figure it out for the life of me.
#comment
blah1
hey1
grrr1
#comment
#blah1
#hey1
#grrr1 (5 Replies)
Can anyone tell me what is the purpose of a substitute variable in the unix programming language and give an example where it may be used?
Thanks! (0 Replies)
hi!
first i want to apologize for two things. my English and (possible) posting in the wrong sub forum (i couldn't find one that fits my question)
I am needing a script that can substitute rm.
the idea is that the operator can/must delete some folders and files from time to time, when the free... (2 Replies)
i'm writing a script that will extract and substitute a certain part of a data.
i'm having trouble with the substituting part ...
Here's my data looks like:
01/01/08-001-23:46:18-01/01/08-23:50:43
01/01/08-003-23:45:19-01/01/08-23:55:49
01/01/08-005-23:52:18-01/01/08-23:58:52
i want to... (6 Replies)
Hi,
I have query terms like this:
a) apple bannana
b) apple bannana AND chickko
c) "milk shake" OR Graphes orange
whereever there is space substitue with AND operator.
I tried like this: (2 Replies)
correct file names are:
*_0.txt
*_1.txt
incorrect file names are:
*_12.txt
*_0123.txt
*_04321.txt
all files that are incorrect need to replace the ending with *_1.txt
therefore need to create a loop to find the wrong files in a dir ->that dont end in _1.txt or _0.txt and then... (3 Replies)
I usually use :
Code:
awk '{gsub(/xxx/,"yyy");print}'
to substitute xxx with yyy.
I have a problem substitute an expression like
Code:
x ' y
Because of the ( ' )
Any idea on how to get over this problem?
Thanks (2 Replies)
Hi there,
i am updating a file on UNIX and have many lines as per below :
listen:x:37:4:Network Admin:/usr/net/nls:
i would like to substitute from the :/usr to the end of the line.
so at the moment im using this :
:s/"\/$/ /g
but i get an error.can anyone help?
thank you (3 Replies)
I have to parse ASCII files, output the relevant data to a comma-delimited file and load it into a database table.
The specs for the file format have been recently updated and one section is causing problems. This is the original layout for that section.
... (2 Replies)
Hello All,
I have a shell script where with the lines below:
echo "${v_sd_dateTime},${RUN_QUEUE_SIZE},${LOAD_AVERAGE},${v_sd_load_list},${v_sd_thread_count_list}" >> ${v_sd_file}
Format of the output :
01/05/2005 08:00:00, RUN_QUEUE_SIZE, LOAD_AVG, CPU_PROD1, CPU_PROD2, THREADS_PROD1,... (1 Reply)
Discussion started by: Supriya_84
1 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)