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Full Discussion: Grep expression between double quotes
Homework and Emergencies Emergency UNIX and Linux Support Grep expression between double quotes Post 302382659 by Scrutinizer on Thursday 24th of December 2009 07:53:40 AM
Old 12-24-2009
Code:
printf 'http://www bla bla "http://xxx" http://yyy\nhttp://zzz\n' | awk '/^["]*http:/&&$0=RS$0RS' RS=\"

It doesn't fix it. It is nitpicking obviously but it is interesting to understand why:

What I meant earlier is if you just look at what the RS does:
Code:
$ printf 'http://www bla bla "http://xxx" http://yyy\nhttp://zzz\n' | awk 1 RS=\"
http://www bla bla
http://xxx
 http://yyy
http://zzz

Then why is using /^http:/ skipping http://zzz ?

---------- Post updated at 13:53 ---------- Previous update was at 13:45 ----------

I found my own answer:
Code:
$ printf 'http://www bla bla "http://xxx" http://yyy\nhttp://zzz\n' | awk NR==3 RS=\"
 http://yyy
http://zzz

up till now I thought awk was working on a line basis but it appears to be working on a record basis, it is just that the default record separator coincides with a newline. Great...
 

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xml::mini::element::doctype

XML::Mini::Element::DocType(3pm)			User Contributed Perl Documentation			  XML::Mini::Element::DocType(3pm)

NAME

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perl v5.10.0							    2009-09-20					  XML::Mini::Element::DocType(3pm)
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