Assuming that all such directories are under your current working directory.
One way is to generate the list of directories, then search them individually.
I have avoided any extensions to "find" syntax because we don't know what Operating System you use.
Code:
find . type d -print | grep '/bbsrc/doc/' |sort | while read DIR
do
find "${DIR}" -type f name \*\.html -print
done
my solaris text talks about the 'find' command... it further goes to talk about an "action" used with the find command.
I am completely confused as to what the {} do with the find comand.
the explanation is this: "A set of braces, {}, delimits where the file name is passed to the command from... (2 Replies)
Hi All,
I am trying to use the find command to search and delete files and have the following scenario. How come the file in the current directory is not getting listed out?
/glo71sw/716/devl/userdata/ftpord --> ls -lt XSKU*
-rw-r--r-- 1 root sys 137493 Jul 7 18:30... (6 Replies)
I am not sure if this question has been answered earlier at the Unix Forums. I tried a search but could not find anything.
So here it goes...
I am looking for a log file under /home.
find /home dklog.log -print
This prints all the directories it traverses while looking for the file and in... (4 Replies)
Hi All,
I have wrote a command to find a and remove all *.apr files ina directory .
Now i got the request as reversed , They want to remove all files except *.apr in the direcory .
Is it possible to do that in a find comand else i have give an explicit find command to all *. files to... (1 Reply)
I'm using this in AIX to find what file contains the value 'batch' in it, in all directories.
find / -type f -exec grep -l batch {} /dev/null \;
My question is, what if I only wanted to search *.sh files, and I wanted to pipe the results to a file called 'batch_find.txt'. How could I code... (3 Replies)
Hello!
I have written this script:
for file in "$( find $dirName -type d )"
do
echo "$file"
echo "hello"
done
but as a result I get all the directories and in the end the work "hello". Shouldn't it print the word "hello" after printing the name of each directory and not in the end?
... (1 Reply)
Hi,
I want to search in the log directory only. This log directory exists at mutiple places in my directory tree. I know that to exclude any directory we have option - prune but can we do the just opposite of it.. just check a single directory and exclude the rest.
thanks (3 Replies)
I was using this find command to search for this string
find /usr/reports -name '*.txt' -type f -exec grep -l tbl_out:add_19 {} \; > /usr/work/junk.txt
My question is, if I want to search another type of file extension besides '*.txt'
how can I include it on the same line to say something... (5 Replies)
Hi all,
I want to use find to 'find' files older than a file.
The command I have come up with so far is
find . -type f ! -newer filename -print | grep -v filename
If I dont use the -v then the filename is included in the output
is there a better way of formulating this command... (1 Reply)
I need to find all files with file names starting with
alert
and ending with
.log
I mean, the following files should be returnrned
alertTST.log
alertabcdefgh.log
How can i do this ? (4 Replies)
Discussion started by: kraljic
4 Replies
LEARN ABOUT CENTOS
shell-quote
SHELL-QUOTE(1) User Contributed Perl Documentation SHELL-QUOTE(1)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.16.3 2010-06-11 SHELL-QUOTE(1)