I have a string "\/scratch\/databases\". I want
to have a new string "\/scratch\/databases" by cutting last '\' character using shell script. I can't do this
Please help me.
Thanks in advance
ThuongTranVN (4 Replies)
Hi all,
Does anyone know how to code in ksh that will remove the first character in a string variable and replace that variable without the first character?
Example:
var1=ktest1 will become var1=test1
var2=rtest2 will become var2=test2
Need help please. (10 Replies)
Hello,
The last character is a comma ,
I have tried the following:
sed -e 's/\,$//' filename-to-read
however - there are still commas at the end of each line...:confused: (5 Replies)
Hello!
Please bare with me, I'm a total newbie to scripting. Here's the sudo code of what I'm trying to do:
Get file name
Does file exist?
If true
get length of file name
get network id (this will be the last 3 numbers of the file name)
loop x 2
If... (1 Reply)
Hi there,
i need some help to remove all occurrences of a certain character at the beginning of a string.
Example: my string is 00102030 and i want to remove all zeros from beginning of string so the result is 102030 (3 Replies)
How can i remove the first and last character of strings like below:
"^^^613*"
"admt130"
"^^^613*"
"123456"
"adg8484"
"DQitYV09dh1C"
Means i wanna remove the quotes("").
Please help (17 Replies)
In bash, how can one remove the last character of a string? In perl, the chop function would remove the last character. However, I do not know how to do the same job in bash.
Many thanks in advance. (12 Replies)
I am outputting a line like this
print $2 "/" $4The last character though is a ":" and I want to remove it. Is there any neat way to remove it? Or am I forced to do something like this:
print $2 "/" substr($4, 1, length($4) - 1)Thanks. (6 Replies)
hello !
I have to remove string between a number and set of characters. For example,
35818 -stress - - -stress - - - - - - DB-3754
44412 caul kid notify DB-3747
54432 roberto -, notify DB-3725
55522 aws _ _int _ _classified 2_a _a 2_m _m 2_classified 2_search... (7 Replies)
Discussion started by: ManoharMa
7 Replies
LEARN ABOUT OSF1
look
look(1) General Commands Manual look(1)NAME
look - Finds lines in a sorted list
SYNOPSIS
look [-df] [-tcharacter] string [file]
The look command prints all lines in a sorted file that begin with string.
OPTIONS
Uses dictionary order; only letters, digits, tabs, and spaces are used in comparisons. Searches without regard to case; treats uppercase
and lowercase as equivalent. Ignores character and characters following it in the search string. If you specify look -tC ABCDE, the
string ABCDE would become (in effect) AB, with CDE being ignored. This option is primarily for shell scripts, in which more than one
string is being processed.
DESCRIPTION
If no file is specified, look searches in the system word list /usr/share/dict/words, with the options -df assumed by default.
The look command uses binary search.
The -d and -f options affect comparisons as in sort.
NOTES
In order to use the -f option, you must first sort file with the sort -f command; otherwise, look displays only lowercase items.
If you do not specify -f, but specify a file (such as /usr/share/dict/words) that has been sorted with sort -f, look may not produce any
output.
EXAMPLES
To search a sorted file called sortfile for all lines that begin with the string as, enter: look as sortfile To search the system word list
for all words beginning with smi, enter: look smi
This might result in: smile smirk smith smithereens Smithfield Smithson smithy smitten
FILES
System word list.
SEE ALSO
Commands: grep(1), sort(1), spell(1)look(1)