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Top Forums Programming Assign NULL to stream objects Post 302379279 by forstudy3 on Thursday 10th of December 2009 07:05:58 AM
Old 12-10-2009
Question Assign NULL to stream objects

Hi,
I am trying to initialize fstream objects to NULL but its throwing an error.Could somebody tell me better way to do this.
I have code in C++ & compiling it using g++ compiler on a Linux box.


Code:
 
ifstream file;
file=NULL;

error

Code:
 
omega.cpp:38: error: no match for 'operator=' in '((OMEGA*)this)->OMEGA::file = 0'
/usr/lib/gcc/i386-redhat-linux/3.4.3/../../../../include/c++/3.4.3/iosfwd:90: note: candidates are: std::basic_ifstream<char, std::char_traits<char> >& std::basic_ifstream<char, std::char_traits<char> >::operator=(const std::basic_ifstream<char, std::char_traits<char> >&)

 

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shevek::rostring(3)					     Library Functions Manual					       shevek::rostring(3)

NAME
shevek::rostring - shevek::rostring is identical to shevek::ostring, but it uses std::string instead of Glib::ustring. SYNOPSIS
#include <iostring.hh> Public Member Functions operator std::string () const Use the result as a string. std::string operator+ (std::string const &that) const Use the result as a string. rostring (std::string const &fmt) Create a string with a constant format. template<typename T1 > rostring (std::string const &fmt, T1 const &a1) Create a string with one argument. template<typename T1 , typename T2 > rostring (std::string const &fmt, T1 const &a1, T2 const &a2) Create a string with two arguments. template<typename T1 , typename T2 , typename T3 > rostring (std::string const &fmt, T1 const &a1, T2 const &a2, T3 const &a3) Create a string with three arguments. template<typename T1 , typename T2 , typename T3 , typename T4 > rostring (std::string const &fmt, T1 const &a1, T2 const &a2, T3 const &a3, T4 const &a4) Create a string with four arguments. template<typename T1 , typename T2 , typename T3 , typename T4 , typename T5 > rostring (std::string const &fmt, T1 const &a1, T2 const &a2, T3 const &a3, T4 const &a4, T5 const &a5) Create a string with five arguments. template<typename T1 , typename T2 , typename T3 , typename T4 , typename T5 , typename T6 > rostring (std::string const &fmt, T1 const &a1, T2 const &a2, T3 const &a3, T4 const &a4, T5 const &a5, T6 const &a6) Create a string with six arguments. template<typename T1 , typename T2 , typename T3 , typename T4 , typename T5 , typename T6 , typename T7 > rostring (std::string const &fmt, T1 const &a1, T2 const &a2, T3 const &a3, T4 const &a4, T5 const &a5, T6 const &a6, T7 const &a7) Create a string with seven arguments. template<typename T1 , typename T2 , typename T3 , typename T4 , typename T5 , typename T6 , typename T7 , typename T8 > rostring (std::string const &fmt, T1 const &a1, T2 const &a2, T3 const &a3, T4 const &a4, T5 const &a5, T6 const &a6, T7 const &a7, T8 const &a8) Create a string with eight arguments. template<typename T1 , typename T2 , typename T3 , typename T4 , typename T5 , typename T6 , typename T7 , typename T8 , typename T9 > rostring (std::string const &fmt, T1 const &a1, T2 const &a2, T3 const &a3, T4 const &a4, T5 const &a5, T6 const &a6, T7 const &a7, T8 const &a8, T9 const &a9) Create a string with nine arguments. Friends std::ostream & operator<< (std::ostream &s, rostring const &o) Send the result to an ostream. Detailed Description shevek::rostring is identical to shevek::ostring, but it uses std::string instead of Glib::ustring. Author Generated automatically by Doxygen for libshevek from the source code. libshevek Fri May 11 2012 shevek::rostring(3)
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