Sponsored Content
Top Forums Shell Programming and Scripting awk command not working from the shell script Post 302377969 by ahmad.diab on Sunday 6th of December 2009 04:39:13 AM
Old 12-06-2009
try the below:-

Code:
cat awk_1:-

/BEGIN DSSUBRECORD/{c=3;next}c-->0 ; /END DSSUBRECORD/{print}
/Owner/{print}
{n2=n1;n1=n;n=$0;if(NR%3==0){printf"%s,%s,%s\n",n2,n1,n}}

---------------------

Code:
a=0
cnt=2
a1="abc.txt"
while [ $a -ne $cnt ]
do
awk -f awk_1 < infile[s] > out_file[s] &
a=$(( $a + 1 ))
done

SmilieSmilieSmilieSmilie
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

cd command is not working in my shell script

Hi, Following is my shell script. #!/bin/tcsh view=$1 image=$2 objfld="obj-ppc-$image" echo $view echo $image echo $objfld echo "cleartool setview $view" cleartool setview $view; cd `cd /vob/ios/sys`; In this "cd" is not working and not getting any error. my shell is "tcsh"... (3 Replies)
Discussion started by: amitrajvarma
3 Replies

2. Shell Programming and Scripting

"sed" command is not working in shell script

Hi All, I am not much strong in shell scripting... I am using sed command in my script to find and replace a string....... This is how script looks : ############# #!/usr/bin/ksh CONFIG_FILE=iom_test.txt FIND=`echo "NIS_FTP_SERVER1=123.456.iom.com"` REPLACE=`echo... (2 Replies)
Discussion started by: askumarece
2 Replies

3. Shell Programming and Scripting

help with shell script: cp command not working, but mv command works...

Hello. I would like to ask your help regarding the cp command. We are using a cp command to create a back-up copy of our file but to no avail. It's just not working. We already checked the file and directory permissions and all seems correct. We have a script (ftp.script) which calls on... (1 Reply)
Discussion started by: udelalv
1 Replies

4. Shell Programming and Scripting

CD command not working in shell script

Hello All, I have tried many permutaion combinations in my shell script but cd command is not working in shell script. Can any one help me out in this. Below is my script. ############ #!/bin/sh set -x on BASE_DIR=/etc/init.d export BASE_DIR cd $BASE_DIR ############# but its... (8 Replies)
Discussion started by: ajaincv
8 Replies

5. Shell Programming and Scripting

Paste command not working in shell script

Hai , When i use paste command in command prompt its giving expected output but not in the script. Below is the example. $cat file 1 2 3 $cat file1 4 5 6 $paste -d ':' file file1 1:4 2:5 3:6 but when i used the same command in script its giving the output as below : 1 2 3 (3 Replies)
Discussion started by: Subbu123
3 Replies

6. Post Here to Contact Site Administrators and Moderators

Unable to pass shell script parameter value to awk command in side the same script

Variable I have in my shell script diff=$1$2.diff id=$2 new=new_$diff echo "My id is $1" echo "I want to sync for user account $id" ##awk command I am using is as below cat $diff | awk -F'~' ''$2 == "$id"' {print $0}' > $new I could see value of $id is not passing to the awk... (0 Replies)
Discussion started by: Ashunayak
0 Replies

7. Shell Programming and Scripting

Unable to pass shell script variable to awk command in same shell script

I have a shell script (.sh) and I want to pass a parameter value to the awk command but I am getting exception, please assist. diff=$1$2.diff id=$2 new=new_$diff echo "My id is $1" echo "I want to sync for user account $id" ##awk command I am using is as below cat $diff | awk... (2 Replies)
Discussion started by: Ashunayak
2 Replies

8. UNIX for Dummies Questions & Answers

Passing shell script parameter value to awk command in side the script

I have a shell script (.sh) and I want to pass a parameter value to the awk command but I am getting exception, please assist. diff=$1$2.diff id=$2 new=new_$diff echo "My id is $1" echo "I want to sync for user account $id" ##awk command I am using is as below cat $diff |... (1 Reply)
Discussion started by: Sarita Behera
1 Replies

9. Shell Programming and Scripting

sed working on command line but file unchanged when execute with Shell script

I have a simple task to replace unix line feed end of line characters with carriage returns. When I run the following “change file in place” sed instruction from the command line all the Line feeds are successfully replaced with Carriage returns. sed -i 's/$/\r/' lf_file.txt But that same... (1 Reply)
Discussion started by: hawkman2k
1 Replies

10. UNIX for Dummies Questions & Answers

Shell script not working but command works in command prompt

Hi everyone I have a problem with my script If I try directly this command /usr/bin/nice -n 19 mysqldump -u root --password="******" wiki_schneider -c | nice -n 19 gzip -9 > /point_de_montage/$(date '+%Y%m%d')-wiki-db.sql.gz It works But if I simply add this command in a script and... (8 Replies)
Discussion started by: picemma
8 Replies
Devel::Refcount(3pm)					User Contributed Perl Documentation				      Devel::Refcount(3pm)

NAME
"Devel::Refcount" - obtain the REFCNT value of a referent SYNOPSIS
use Devel::Refcount qw( refcount ); my $anon = []; print "Anon ARRAY $anon has " . refcount($anon) . " reference "; my $otherref = $anon; print "Anon ARRAY $anon now has " . refcount($anon) . " references "; DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value. FUNCTIONS
$count = refcount($ref) Returns the reference count of the object being pointed to by $ref. COMPARISON WITH SvREFCNT This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed, whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH, CODE, GLOB and Regexp types) as well. Consider the following example program: use Devel::Peek qw( SvREFCNT ); use Devel::Refcount qw( refcount ); sub printcount { my $name = shift; printf "%30s has SvREFCNT=%d, refcount=%d ", $name, SvREFCNT($_[0]), refcount($_[0]); } my $var = []; printcount 'Initially, $var', $var; my $othervar = $var; printcount 'Before CODE ref, $var', $var; printcount '$othervar', $othervar; my $code = sub { undef $var }; printcount 'After CODE ref, $var', $var; printcount '$othervar', $othervar; This produces the output Initially, $var has SvREFCNT=1, refcount=1 Before CODE ref, $var has SvREFCNT=1, refcount=2 $othervar has SvREFCNT=1, refcount=2 After CODE ref, $var has SvREFCNT=2, refcount=2 $othervar has SvREFCNT=1, refcount=2 Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this case. Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it. After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the new anonymous CODE block. PURE-PERL FALLBACK An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in pure perl using the "B" module is used instead. This will behave identically, but is much slower. Rate pp xs pp 225985/s -- -66% xs 669570/s 196% -- SEE ALSO
o Test::Refcount - assert reference counts on objects AUTHOR
Paul Evans <leonerd@leonerd.org.uk> perl v5.14.2 2011-11-15 Devel::Refcount(3pm)
All times are GMT -4. The time now is 05:30 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy