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Top Forums Shell Programming and Scripting How to calculate the difference between two adjacent columns? Post 302377314 by rdcwayx on Thursday 3rd of December 2009 06:09:47 PM
Old 12-03-2009
Code:
awk 'function abs(val) {return val>0?val:-val } 
for (i=1; i<NF; i++) {if (abs($i - $(i+1))>10) print 1; else print 0}' urfile


Last edited by rdcwayx; 12-03-2009 at 07:35 PM..
 

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Time::Seconds(3pm)					 Perl Programmers Reference Guide					Time::Seconds(3pm)

NAME
Time::Seconds - a simple API to convert seconds to other date values SYNOPSIS
use Time::Piece; use Time::Seconds; my $t = localtime; $t += ONE_DAY; my $t2 = localtime; my $s = $t - $t2; print "Difference is: ", $s->days, " "; DESCRIPTION
This module is part of the Time::Piece distribution. It allows the user to find out the number of minutes, hours, days, weeks or years in a given number of seconds. It is returned by Time::Piece when you delta two Time::Piece objects. Time::Seconds also exports the following constants: ONE_DAY ONE_WEEK ONE_HOUR ONE_MINUTE ONE_MONTH ONE_YEAR ONE_FINANCIAL_MONTH LEAP_YEAR NON_LEAP_YEAR Since perl does not (yet?) support constant objects, these constants are in seconds only, so you cannot, for example, do this: "print ONE_WEEK->minutes;" METHODS
The following methods are available: my $val = Time::Seconds->new(SECONDS) $val->seconds; $val->minutes; $val->hours; $val->days; $val->weeks; $val->months; $val->financial_months; # 30 days $val->years; The methods make the assumption that there are 24 hours in a day, 7 days in a week, 365.24225 days in a year and 12 months in a year. (from The Calendar FAQ at http://www.tondering.dk/claus/calendar.html) AUTHOR
Matt Sergeant, matt@sergeant.org Tobias Brox, tobiasb@tobiasb.funcom.com BalieXXzs SzabieXX (dLux), dlux@kapu.hu LICENSE
Please see Time::Piece for the license. Bugs Currently the methods aren't as efficient as they could be, for reasons of clarity. This is probably a bad idea. perl v5.12.1 2010-04-26 Time::Seconds(3pm)
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