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Top Forums Shell Programming and Scripting AWK: Retrieving names of variables passed with -v Post 302377220 by John Mac on Thursday 3rd of December 2009 12:05:01 PM
Old 12-03-2009
AWK: Retrieving names of variables passed with -v

I'm an experienced awk user, but this one has me stumped. I have an awk script which is called from a UNIX command line as you'd expect:

Code:
myscript.awk -v foo=$1 -v bar=$2 filename

My question is this: is there a mechanism for determining the names of the -v variables within a script?

ARGV doesn't include them (and quite rightly so, since they're not arguments).

I'd like my script to be able to parse a list of variables passed, so that I can print an error message along the lines of "Unknown variable name - please check and try again", or call a Usage() function, or some such.

Thanks in advance, guys 'n' gals.

Last edited by John Mac; 12-03-2009 at 01:17 PM..
 

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IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)
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