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Multiple variables to be passed in a loop

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# 1  
Multiple variables to be passed in a loop


I need to pass the multiple values of src1 to another variable. I managed to print it but not sure how to assign it to a variable in a loop.

echo $src1|awk 'BEGIN {FS=","} {for(i=1;i<=NF;i++) print $i}'

I need to pass the value as

# 2  
Not sure what you require. Would this fit your needs:
IFS=","; for i in $src1; do src2=$i; echo $src2; done

This User Gave Thanks to RudiC For This Post:
# 3  
You might want to give this a try:

while IFS="=" read part1 part2 ; do
     print - "part1 is: $part1   part2 is $part2"
done < /path/to/file

Where file might contain:


Instead of a file you can use a pipeline or a here-document as well, i.e.:

some-command | while IFS="=" read part1 part2 ; do
     print - "part1 is: $part1   part2 is $part2"

The interesting part of the code is this:

IFS="<some-char>" read var1 var2 [var3....]

Setting the IFS variable to some character means the input is split up into "words" at exactly this character. The variables ("var1", "var2", ...) are assigned these words one after the other. If your input would look like this:


You could write:
IFS=":" read first second third
echo $first
echo $second
echo $third

I hope this helps.

This User Gave Thanks to bakunin For This Post:
# 4  
can you explain what you want as output?

you can assign simply
y=`echo $src1|awk 'BEGIN {FS=","} {for(i=1;i<=NF;i++) print $i}'`

but not sure what youu mean by variable in a loop
# 5  
Apologies for not being clear enough in posting my requirements. Thanks for all your inputs. I have now got what I wanted.

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