Sponsored Content
Full Discussion: test expr VS [ expr ]
Top Forums Shell Programming and Scripting test expr VS [ expr ] Post 302377094 by ashok.g on Thursday 3rd of December 2009 06:17:44 AM
Old 12-03-2009
test expr VS [ expr ]

What is the difference between test expr VS [ expr ].
For example :
Code:
if test 5 -eq 6
echo "Wrong"

and
Code:
if [ 5 -eq 6 ]
echo "Wrong"

bot will give the same output as Wrong.
Now, what is the difference between these two? though they are producing the same result why we need two?

Any answer will be appreciated,

Last edited by pludi; 12-03-2009 at 07:21 AM.. Reason: code tags, please...
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

expr

Hello! I want to evaluate some mathematical expressions in a script and I try to use 'expr' command. Unfortunatally, when I have, for example, expr 8.2 + 6 the result is 'expr: non-numeric argument' Why ? I work on SunOs 5.7. Thanks in advance Nathe (5 Replies)
Discussion started by: Nathe
5 Replies

2. UNIX for Dummies Questions & Answers

using the expr command

Hi friends how can i execute expr $va1 * $var2 provided i m not supposed to use '/' also the nglob variable is turned off. (4 Replies)
Discussion started by: ashishj
4 Replies

3. Red Hat

how to use expr

i am new to shell programming, currently using redhat linux of version 2.4.20-8. i have problem in executing expr command in the following shell script $ x=5 $ x='expr $x + 1' $ echo $x the output is displaying always expr $x + 1 Pls guide me for the above query (3 Replies)
Discussion started by: saikumarm80
3 Replies

4. Shell Programming and Scripting

the expr \*

$ cat > mtable #!/bin/sh # #Script to test for loop # # if then echo "Error - Number missing form command line argument" echo "Syntax : $0 number" echo "Use to print multiplication table for given number" exit 1 fi n=$1 for i in 1 2 3 4 5 6 7 8 9 10 do echo "$n * $i = `expr $i \*... (1 Reply)
Discussion started by: jackel7777
1 Replies

5. UNIX for Dummies Questions & Answers

expr ?!

Hey there i want to subtract the content from $b from $a. Each variable has got 18 values (normal numbers from 0 - 99). How can i subtract them? I know i have to use the expr command, this is what i have till now: a=`cat Tabelle.dat | awk {'print $4'} | awk -F: {'print $1'}` b=`cat... (1 Reply)
Discussion started by: Mad van Bert
1 Replies

6. UNIX for Dummies Questions & Answers

Performance of let and expr

i have been told that 'let' is faster than 'expr' in terms of performance. Is this correct? if yes, why is it so? i am not able to see any performance difference in small arithmetic operations. Thanks (3 Replies)
Discussion started by: pandeesh
3 Replies

7. Shell Programming and Scripting

Error with expr - "expr: syntax error"

Hi All, I'm writing a shell script in KSH, where I want to store the filename, total record count and actual record count of all the source files. The source files reside in 4 different sub-folders under the same root folder. Below is code: #!/usr/bin/ksh... (6 Replies)
Discussion started by: jagari
6 Replies

8. UNIX for Dummies Questions & Answers

Issues with 'expr'

Hi, I have a text file where i define all the inputs to my shell script: IP=1.2.3.4 PC=1234 In the shell script, i am trying to read the input variables from the above mentioned text file: #!/bin/bash #usage IP=expr cat /tmp/input.txt | grep IP| cut -d "=" -f2 PC=expr cat... (4 Replies)
Discussion started by: akarnya
4 Replies

9. Shell Programming and Scripting

If + expr

Hi I have bellow script: t1=`cat node1.txt | grep thread1 | cut -f2 -d '-'` t2=`cat node2.txt | grep thread2 | cut -f2 -d '-'` t3=`cat node1_rcat.txt | grep thread1 | cut -f2 -d '-'` t4=`cat node2_rcat.txt | grep thread2 | cut -f2 -d '-'` if ]; then echo "no restore" >> log.log... (6 Replies)
Discussion started by: primo102
6 Replies

10. Shell Programming and Scripting

Nn$( expr $n + 1)

HI there I am trying to understand Shell scripting to create my own, I am attempting a few examples can anyone tell me what this means?n=$( expr $n + 1)Tried looking on the internet, but just cannot find its anywhere :( .Help please (4 Replies)
Discussion started by: steve2015
4 Replies
Devel::Refcount(3pm)					User Contributed Perl Documentation				      Devel::Refcount(3pm)

NAME
"Devel::Refcount" - obtain the REFCNT value of a referent SYNOPSIS
use Devel::Refcount qw( refcount ); my $anon = []; print "Anon ARRAY $anon has " . refcount($anon) . " reference "; my $otherref = $anon; print "Anon ARRAY $anon now has " . refcount($anon) . " references "; DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value. FUNCTIONS
$count = refcount($ref) Returns the reference count of the object being pointed to by $ref. COMPARISON WITH SvREFCNT This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed, whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH, CODE, GLOB and Regexp types) as well. Consider the following example program: use Devel::Peek qw( SvREFCNT ); use Devel::Refcount qw( refcount ); sub printcount { my $name = shift; printf "%30s has SvREFCNT=%d, refcount=%d ", $name, SvREFCNT($_[0]), refcount($_[0]); } my $var = []; printcount 'Initially, $var', $var; my $othervar = $var; printcount 'Before CODE ref, $var', $var; printcount '$othervar', $othervar; my $code = sub { undef $var }; printcount 'After CODE ref, $var', $var; printcount '$othervar', $othervar; This produces the output Initially, $var has SvREFCNT=1, refcount=1 Before CODE ref, $var has SvREFCNT=1, refcount=2 $othervar has SvREFCNT=1, refcount=2 After CODE ref, $var has SvREFCNT=2, refcount=2 $othervar has SvREFCNT=1, refcount=2 Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this case. Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it. After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the new anonymous CODE block. PURE-PERL FALLBACK An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in pure perl using the "B" module is used instead. This will behave identically, but is much slower. Rate pp xs pp 225985/s -- -66% xs 669570/s 196% -- SEE ALSO
o Test::Refcount - assert reference counts on objects AUTHOR
Paul Evans <leonerd@leonerd.org.uk> perl v5.14.2 2011-11-15 Devel::Refcount(3pm)
All times are GMT -4. The time now is 07:16 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy