looking to do the following...
What the data looks like
server1 02/01/2008 groups 10
server1 03/01/2008 groups 15
server1 04/01/2008 groups 20
server2 02/01/2008 users 50
server2 03/01/2008 users 75
server2 04/01/2008 users 100
server2 04/01/2008 users 125
What I would like the... (1 Reply)
I have a file like the one given below
P1|V1|V2
P1|V1|V3
P1V1|V2
P2|V1|V4
P2|V2|V6
P2|V1|V4
I want it convert to
P1|V1|V2|V2|V3
P2|V1|V4|V2|V6
2nd and 3rd column should be considered as together and so the tird row is duplicate
Any ideas? (3 Replies)
I'm working on a different stage of a project that someone helped me address elsewhere in these threads.
The .docs I'm cycling through look roughly like this:
1 of 26 DOCUMENTS
Copyright 2010 The Age Company Limited
All Rights Reserved
The Age (Melbourne, Australia)
November 27, 2010... (9 Replies)
I have 1000s of these rows that I would like to transpose to columns. However I would like the transpose every 3 consecutive rows to columns like below, sorted by column 3 and provide a total for each occurrences. Finally I would like a grand total of column 3.
21|FE|41|0B
50\65\78
15... (2 Replies)
I have to create a Perl script which will transpose the data output from my experiment, from columns to rows, in order for me to analyse the data.
I am a complete Perl novice so any help would be greatly appreciated.
The data as it stands looks like this:
Subject Condition Fp1 ... (12 Replies)
Hi, I need to transpose columns of my files into rows and save it as individual files. sample contents of the file below.
0.9120 0.7782 0.6959 0.6904 0.6322 0.8068 0.9082
0.9290 0.7272 0.9870 0.7648 0.8053 0.8300 0.9520
0.8614 0.6734 0.7910 0.6413 0.7126 0.7364 0.8491
0.8868 0.7586 0.8949... (8 Replies)
Here is the contents of an input file.
A,1,2,3,4
10,aaa,bbb,ccc,ddd
11,eee,fff,ggg,hhh
12,iii,jjj,lll,mmm
13,nnn,ooo,ppp
I wanted the output to be
A
10 1 aaa
10 2 bbb
10 3 ccc
10 4 ddd
11 1 eee
11 2 fff
11 3 ggg
11 4 hhh .....
and so on How to do it in ksh... (9 Replies)
Okay folks, here's a question. I tried searching but couldn't find exactly what I needed.
I have a text file (excerpt below). This text file is an extract I did from several hundred pages of datasheets using grep so I could look only at the site history for each site. The problem is that... (2 Replies)
Hi,
I am trying to transpose rows to columns for thousands of records. The problem is there are records that have the same lines that need to be separated. the input file as below:-
ID 1A02_HUMAN
AC P01892; O19619; P06338; P10313; P30444; P30445; P30446; P30514;
AC Q29680; Q29837;... (2 Replies)
Discussion started by: redse171
2 Replies
LEARN ABOUT DEBIAN
adjtime
ADJTIME(3) Linux Programmer's Manual ADJTIME(3)NAME
adjtime - correct the time to synchronize the system clock
SYNOPSIS
int adjtime(const struct timeval *delta, struct timeval *olddelta);
Feature Test Macro Requirements for glibc (see feature_test_macros(7)):
adjtime(): _BSD_SOURCE
DESCRIPTION
The adjtime() function gradually adjusts the system clock (as returned by gettimeofday(2)). The amount of time by which the clock is to be
adjusted is specified in the structure pointed to by delta. This structure has the following form:
struct timeval {
time_t tv_sec; /* seconds */
suseconds_t tv_usec; /* microseconds */
};
If the adjustment in delta is positive, then the system clock is speeded up by some small percentage (i.e., by adding a small amount of
time to the clock value in each second) until the adjustment has been completed. If the adjustment in delta is negative, then the clock is
slowed down in a similar fashion.
If a clock adjustment from an earlier adjtime() call is already in progress at the time of a later adjtime() call, and delta is not NULL
for the later call, then the earlier adjustment is stopped, but any already completed part of that adjustment is not undone.
If olddelta is not NULL, then the buffer that it points to is used to return the amount of time remaining from any previous adjustment that
has not yet been completed.
RETURN VALUE
On success, adjtime() returns 0. On failure, -1 is returned, and errno is set to indicate the error.
ERRORS
EINVAL The adjustment in delta is outside the permitted range.
EPERM The caller does not have sufficient privilege to adjust the time. Under Linux the CAP_SYS_TIME capability is required.
CONFORMING TO
4.3BSD, System V.
NOTES
The adjustment that adjtime() makes to the clock is carried out in such a manner that the clock is always monotonically increasing. Using
adjtime() to adjust the time prevents the problems that can be caused for certain applications (e.g., make(1)) by abrupt positive or nega-
tive jumps in the system time.
adjtime() is intended to be used to make small adjustments to the system time. Most systems impose a limit on the adjustment that can be
specified in delta. In the glibc implementation, delta must be less than or equal to (INT_MAX / 1000000 - 2) and greater than or equal to
(INT_MIN / 1000000 + 2) (respectively 2145 and -2145 seconds on i386).
BUGS
A longstanding bug meant that if delta was specified as NULL, no valid information about the outstanding clock adjustment was returned in
olddelta. (In this circumstance, adjtime() should return the outstanding clock adjustment, without changing it.) This bug is fixed on
systems with glibc 2.8 or later and Linux kernel 2.6.26 or later.
SEE ALSO adjtimex(2), gettimeofday(2), time(7)COLOPHON
This page is part of release 3.44 of the Linux man-pages project. A description of the project, and information about reporting bugs, can
be found at http://www.kernel.org/doc/man-pages/.
Linux 2008-06-22 ADJTIME(3)