11-19-2009
10 More Discussions You Might Find Interesting
1. UNIX for Dummies Questions & Answers
Hi there,
When I run top on my machine it says I have 497M swap space in use, and 380M swap space free,
but I have only allocated 512M swap space to the machine!!!!
Does anyone know how swap used is calculated in the top command?
Thanks... (1 Reply)
Discussion started by: chorgan
1 Replies
2. Solaris
Hi Folks,
This is my first post here - so nice to meet u all :-)
Recently i was trying to dig a little bit into the memory structure of my machine and due to the lack of concept, cannot figure out a calculation.
This is how it goes:
1) My swap slice is at the usual /dev/dsk/c0t1d0s1... (0 Replies)
Discussion started by: s4g3
0 Replies
3. UNIX for Dummies Questions & Answers
Hi All,
Will df+du=Total space allocted for a file system??
Is the above correct. Please correct me If iam wrong.
In one my programs the above is not happening.
Please help me out.
Many thanks.
Regards,
Manas (2 Replies)
Discussion started by: manas6
2 Replies
4. Solaris
i am working with solaris 9 and my disk usages are
# df -k
Filesystem kbytes used avail capacity Mounted on
/dev/dsk/c0t0d0s0 2148263 1902721 202577 91% /
/proc 0 0 0 0% /proc
mnttab 0 0 0 ... (3 Replies)
Discussion started by: smartgupta
3 Replies
5. Solaris
Using 'swap -l' I can get the disk based portion of swap.
What if the swap (/usr/bin/swap) command isn't available. What are my options then? Could I get this number with kstat?
From /etc/vfstab, I can see the partitions that are reserved for swap.
/dev/dsk/c0d0s1
using df however not... (3 Replies)
Discussion started by: Devyn
3 Replies
6. Solaris
Hey guys,
I am somewhat new to Solaris - and very new when it comes to mounts.
My problem is that when I installed Solaris, I allocated way too little diskspace to my / mount (it first became obvious now, however, because of new needs).
bash-3.00# df -h
Filesystem size ... (25 Replies)
Discussion started by: brightstorm
25 Replies
7. UNIX for Dummies Questions & Answers
Hello,
I need to find the total allocated disk space for the home directory.
How can i find that in unix?(in GB).
Thanks. (4 Replies)
Discussion started by: kailash19
4 Replies
8. Solaris
Hi all,
The environment we're using is a T5440 running Solaris 10 LDOMs and zones configured within the LDOM. The LDOM has 32Gb of RAM and 32Gb of swap.
Last week, we had an issue where the MQ server on zone 3 crashed as it ran out of swap, apparently caused by zone 2 usage. I understand that... (7 Replies)
Discussion started by: JerryHone
7 Replies
9. Red Hat
Hi All,
I have a RAM of around 11 gig and swap of around 18 G in my Linux Server.
But at some times , I find that All the RAM and 5 gig of swap is used in server...and i also got some advice from our discussion forums to increase the RAM .
But nowadays what happens is the all the RAM... (1 Reply)
Discussion started by: jegaraman
1 Replies
10. Shell Programming and Scripting
Hi ,
I Would like to know the space allocated by adding up all the allocated space to group of filesystems ..
example ,
df -h|grep /db | awk '{ print $4 }' ---> giving me all the used space on the filesystem but need to know the total used space by adding up all the values (3 Replies)
Discussion started by: nsankineni
3 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)
NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS
--predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO
bup-midx(1), bup-save(1)
BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown- bup-margin(1)