I write a sh script that zip and copy to tape all files that older then 2 hours.
1. The way I choose is - touch a file with "now - 2 hours", then use fine with '! -newer'
2. Do you have any other idea to do it ?
tnx. (1 Reply)
I Have a long file like this
123122312 05/06/12
123123456 05/06/14
I want to take the difference of dates in two lines & print difference sidewise for the whole long files.
Pl help me out. (1 Reply)
I have the script which appends month and year to the name of the
file. Now every time when I append the month-year combination I
have to subtract 2 months from the current date and then append
it, since we are sending our vendor 2 months prior worth of data
eveytime.
#! /usr/bin/ksh
... (5 Replies)
the given time is:
12:13:00
how do i subtract a 10 minutes from any given time?
date '12:13:00' '-10 min'
also tried this:
date +12:13:00 '-10 min' (2 Replies)
I have a file with name and date---
$ cat file.log
userA 01-06-2014
userB 25-05-2014
userC 16-05-2014
userC 01-03-2014
I want to search for the current date and get the name for that date. If current date is not found, go back 1 day and search and so on till it finds the... (2 Replies)
Hi,
I am reading a particular date from a file using below command
WFLWDATE=$(sed '2q;d' FileA.prm)
The echo command outputs the correct date in variable WFLWDATE
Now I want to subtract 5 minutes from this variable. I am on AIX and unable to get anything working as expected.
Can you... (1 Reply)
Hi,
Can you please let me know code for the below (in korn shell)
a) Subtract month(s) from given date
b) Subtract day(s) from give date
c) Subtract month(s) from given timestamp
d) Subtract day(s) from give timestamp (1 Reply)
SunOS -s 5.10 Generic_147440-04 sun4u sparc SUNW,SPARC-Enterprise
Hi,
In a folder, there are files. I have a script which reads the current date and subtract the modification date of each file.
How do I achieve this?
Regards,
Joe (2 Replies)
current date command runs well
awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
subtract 30 days fails
awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
LEARN ABOUT PHP
date_parse_from_format
DATE_PARSE_FROM_FORMAT(3) 1 DATE_PARSE_FROM_FORMAT(3)date_parse_from_format - Get info about given date formatted according to the specified formatSYNOPSIS
array date_parse_from_format (string $format, string $date)
DESCRIPTION
Returns associative array with detailed info about given date.
PARAMETERS
o $format
- Format accepted by DateTime.createFromFormat(3).
o $date
- String representing the date.
RETURN VALUES
Returns associative array with detailed info about given date.
EXAMPLES
Example #1
date_parse_from_format(3) example
<?php
$date = "6.1.2009 13:00+01:00";
print_r(date_parse_from_format("j.n.Y H:iP", $date));
?>
The above example will output:
Array
(
[year] => 2009
[month] => 1
[day] => 6
[hour] => 13
[minute] => 0
[second] => 0
[fraction] =>
[warning_count] => 0
[warnings] => Array
(
)
[error_count] => 0
[errors] => Array
(
)
[is_localtime] => 1
[zone_type] => 1
[zone] => -60
[is_dst] =>
)
SEE ALSO DateTime.createFromFormat(3), checkdate(3).
PHP Documentation Group DATE_PARSE_FROM_FORMAT(3)