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Full Discussion: Using arrays in shell
Top Forums Shell Programming and Scripting Using arrays in shell Post 302366489 by anish on Thursday 29th of October 2009 04:12:03 PM
Old 10-29-2009
I am assuming I am running ksh88. I don't have KSH_VERSION variable defined.

Code:
#!/usr/bin/ksh
set +A MASTERARRAY SQLUPDATE SQLUPDATE2 END_OF_ARRAY
set +A SQLUPDATE_DAILY  update12 update22
set +A SQLUPDATE_ONETIME  update32 update42
for element in "${MASTERARRAY[@]}"
do
  case $element in (END_OF_ARRAY) break;; esac
  eval "set -- \"\${${element}[@]}\" "
  for e
  do
      case $e in (END_OF_ARRAY) break;; esac
      printf "\nArray: %s\n" "$e"
  done
done

1. I added extra parenthesis in front of END_OF_ARRAY
2. When I run the script. I don't get any error message but nothing prints
 

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ARRAY_REPLACE(3)							 1							  ARRAY_REPLACE(3)

array_replace - Replaces elements from passed arrays into the first array

SYNOPSIS
array array_replace (array $array1, array $array2, [array $...]) DESCRIPTION
array_replace(3) replaces the values of $array1 with values having the same keys in each of the following arrays. If a key from the first array exists in the second array, its value will be replaced by the value from the second array. If the key exists in the second array, and not the first, it will be created in the first array. If a key only exists in the first array, it will be left as is. If several arrays are passed for replacement, they will be processed in order, the later arrays overwriting the previous values. array_replace(3) is not recursive : it will replace values in the first array by whatever type is in the second array. PARAMETERS
o $array1 - The array in which elements are replaced. o $array2 - The array from which elements will be extracted. o $... - More arrays from which elements will be extracted. Values from later arrays overwrite the previous values. RETURN VALUES
Returns an array, or NULL if an error occurs. EXAMPLES
Example #1 array_replace(3) example <?php $base = array("orange", "banana", "apple", "raspberry"); $replacements = array(0 => "pineapple", 4 => "cherry"); $replacements2 = array(0 => "grape"); $basket = array_replace($base, $replacements, $replacements2); print_r($basket); ?> The above example will output: Array ( [0] => grape [1] => banana [2] => apple [3] => raspberry [4] => cherry ) SEE ALSO
array_replace_recursive(3), array_merge(3). PHP Documentation Group ARRAY_REPLACE(3)
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