hi ,
This function actually gives me the last month but as a numeric value what should i do to get it as suppose :Jul
date '+%b %Y' |
{
read MONTH YEAR
MONTH=`expr "$MONTH" - 1`
echo $MONTH
}
Thanks.
Rooh (2 Replies)
Dear friends,
I am new to Unix/Linux. I am trying to run following query but getting an error msg... Please can u people help me in this?
Query:
echo "select status_ac from db_acct where acct_num=AAA000337" | dbaccess elstest
Error:
217: Column (amd000337) not found in any table in the... (2 Replies)
i have an variable mydate=2008Nov07
i want o/p as in variable mymonth=11 (i.e nov comes on 11 number month)
i want some command to do this for any month without using any loop.
plz help me (1 Reply)
Hi All,
I have 1 million records file. Using awk, I am counting the number of records. But as the number is huge, after crossing a number, awk is displaying it in exponential format.
At the end, I need to verify this count given by awk with expected count.
But as it is in exponential format,... (3 Replies)
Request if some one could provide me shell script that converts the below "input file" to "CSV format file" given
Name Domain Contact Phone Email Location
----------------------- ------------------------------------------------ ------- ----- ---------------------------------... (7 Replies)
Hello All,
I am trying to come up with a shell script to count a specific word in a logfile on each day of this month, last month and the month before. I need to produce this report and email it to customer.
Any ideas would be appreciated! (5 Replies)
Hi guys
I am having this strange issue.Well my requirement is like below
Compare two values between flat file and oracle DB
Via perl script I am easily getting the rowcount
Now I connect sql plus via perl and the column value that returns is string
my $sqlplus_settings = '';
my... (7 Replies)
Hi,
I know this must be very simple and stupid question
but I could not find a proper answer anywhere else,
My script generates numeric values in the following format
3.01234567891E+03
I use %.11E in printf formatting, but I need to list my numbers as
0.30123456789E+04
basicly I... (14 Replies)
hi i want to convert date procured from sone operation which will be in 24hr format to 12 hr format displaying AM and PM
# date -d @1362545068
Tue Mar 5 23:44:28 EST 2013
#
this Tue Mar 5 23:44:28 EST 2013
i want to convert it so that output is as below
Tue... (2 Replies)
Discussion started by: vivek d r
2 Replies
LEARN ABOUT NETBSD
cal
CAL(1) BSD General Commands Manual CAL(1)NAME
cal -- displays a calendar
SYNOPSIS
cal [-3hjry] [-A after] [-B before] [-d day-of-week] [-R reform-spec] [[month] year]
DESCRIPTION
cal displays a simple calendar. If arguments are not specified, the current month is displayed. The options are as follows:
-3 Same as ``-A 1 -B 1''.
-A after
Display after months after the specified month.
-B before
Display before months before the specified month.
-d day-of-week
Specifies the day of the week on which the calendar should start. Valid values are 0 through 6, presenting Sunday through Saturday,
inclusively. The default output starts on Sundays.
-h Highlight the current day, if present in the displayed calendar. If output is to a terminal, then the appropriate terminal sequences
are used, otherwise overstriking is used. If more than one -h is used and output is to a terminal, the current date will be high-
lighted in inverse video instead of bold.
-j Display Julian dates (days one-based, numbered from January 1).
-R reform-spec
Selects an alternate Gregorian reform point from the default of September 3rd, 1752. The reform-spec can be selected by one of the
built-in names (see NOTES for a list) or by a date of the form YYYY/MM/DD. The date and month may be omitted, provided that what is
specified uniquely selects a given built-in reform point. If an exact date is specified, then that date is taken to be the first
missing date of the Gregorian Reform to be applied.
-r Display the month in which the Gregorian Reform adjustment was applied, if no other month or year information is given. If used in
conjunction with -y, then the entire year is displayed.
-y Display a calendar for the current year.
If no parameters are specified, the current month's calendar is displayed. A single parameter specifies the year and optionally the month in
ISO format: ``cal 2007-12'' Two parameters denote the month (1 - 12) and year. Note that the century must be included in the year.
A year starts on Jan 1.
NOTES
In the USA and Great Britain the Gregorian Reformation occurred in 1752. By this time, most countries had recognized the reformation
(although a few did not recognize it until the 1900's.) Eleven days following September 2, 1752 were eliminated by the reformation, so the
calendar for that month is a bit unusual.
In view of the chaotic way the Gregorian calendar was adopted throughout the world in the years between 1582 and 1928 make sure to take into
account the date of the Gregorian Reformation in your region if you are checking a calendar for a very old date.
cal has a decent built-in list of Gregorian Reform dates and the names of the countries where the reform was adopted:
Italy Oct. 5, 1582 Denmark Feb. 19, 1700
Spain Oct. 5, 1582 Great Britain Sep. 3, 1752
Portugal Oct. 5, 1582 Sweden Feb. 18, 1753
Poland Oct. 5, 1582 Finland Feb. 18, 1753
France Dec. 12, 1582 Japan Dec. 20, 1872
Luxembourg Dec. 22, 1582 China Nov. 7, 1911
Netherlands Dec. 22, 1582 Bulgaria Apr. 1, 1916
Bavaria Oct. 6, 1583 U.S.S.R. Feb. 1, 1918
Austria Jan. 7, 1584 Serbia Jan. 19, 1919
Switzerland Jan. 12, 1584 Romania Jan. 19, 1919
Hungary Oct. 22, 1587 Greece Mar. 10, 1924
Germany Feb. 19, 1700 Turkey Dec. 19, 1925
Norway Feb. 19, 1700 Egypt Sep. 18, 1928
The country known as Great Britain can also be referred to as England since that has less letters and no spaces in it. This is meant only as
a measure of expediency, not as a possible slight to anyone involved.
HISTORY
A cal command appeared in Version 6 AT&T UNIX.
BSD December 21, 2007 BSD