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Operating Systems AIX ssh public key setup questions. Post 302366041 by haroon_a on Wednesday 28th of October 2009 04:01:21 PM
Old 10-28-2009
Quote:
Originally Posted by zxmaus
Hi,

the good news - your script works Smilie It does exactly what you tell it to do.

The bad news - if you want just remote execution you should rather use the rsh command facilities rather than ssh and than pull the output. Obviously bad for security.

Kind regards
zxmaus
Thanks for the hints and advise. I'll look into rsh.

In the meantime, I am working on my script, and want to re-use portions of my code (BTW, I'm not an expert in shell scripting), so I decided to use a function. So, here's what I'm trying to use function, but I can't get it to work, Please bare with me.
Code:
#!/bin/sh
#some codes here
...
printThisWord "Hey, You printed me!!"
...
# some more code here
 
printThisWord () {
echo "$1"
}

However, when I run my script, it says:
Code:
myscript.sh[32]: printThisWord:  not found

The rest of the script gets executed.

Please advise...

Thanks.
 

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SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
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