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Full Discussion: Understanding array in array
Top Forums Shell Programming and Scripting Understanding array in array Post 302365184 by majormark on Monday 26th of October 2009 08:56:44 AM
Old 10-26-2009
Instead of removing each element, you can 'clean up' the array by re-assignation
Code:
my @array1; 
$array1[1]=11; 
print "before: $#array1\n"; 
my @array2; 
@array1=@array2; 
print "after: $#array1\n";

 

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ARRAY_INTERSECT(3)							 1							ARRAY_INTERSECT(3)

array_intersect - Computes the intersection of arrays

SYNOPSIS
array array_intersect (array $array1, array $array2, [array $...]) DESCRIPTION
array_intersect(3) returns an array containing all the values of $array1 that are present in all the arguments. Note that keys are pre- served. PARAMETERS
o $array1 - The array with master values to check. o $array2 - An array to compare values against. o $... - A variable list of arrays to compare. RETURN VALUES
Returns an array containing all of the values in $array1 whose values exist in all of the parameters. EXAMPLES
Example #1 array_intersect(3) example <?php $array1 = array("a" => "green", "red", "blue"); $array2 = array("b" => "green", "yellow", "red"); $result = array_intersect($array1, $array2); print_r($result); ?> The above example will output: Array ( [a] => green [0] => red ) NOTES
Note Two elements are considered equal if and only if (string) $elem1 === (string) $elem2. In words: when the string representation is the same. SEE ALSO
array_intersect_assoc(3), array_diff(3), array_diff_assoc(3). PHP Documentation Group ARRAY_INTERSECT(3)
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