Login or Register to Ask a Question and Join Our Community

Sponsored Content
Full Discussion: Howto Print File Path or Print the Filename
Top Forums Shell Programming and Scripting Howto Print File Path or Print the Filename Post 302360420 by zaxxon on Friday 9th of October 2009 01:00:11 AM
Old 10-09-2009
It's a lot of find runs depending on how many files you are searching for. To make it a bit more efficient I would go with something like this for example:
Code:
find /opt -type f -name "*.jpg" -o -name "*.gif" -print > found.out
grep -f list found.out > positive_list.out
grep -fv list found.out > negative_list.out

 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

perl: howto print to screen & filehandle

Hello, I need to print messages both to screen and to file handle in perl , like tee does in unix . Any suggestions ? Thanks (2 Replies)
Discussion started by: Alalush
2 Replies

2. Shell Programming and Scripting

print the filename

#!/bin/ksh for files in `ls *.gz` do gunzip -c $files | awk -v s=$files -F\" '{print s","$6}' done I have tried FILENAME parameter but it did not work please help. (1 Reply)
Discussion started by: harshakirans
1 Replies

3. UNIX for Dummies Questions & Answers

find locked files, print file path, unlock file

using OS X and the Terminal, I'd like to find all locked files in a specified directory, unlock them, and print a list of those files that were unlocked how can I do this? I'm familiar with chflags nouchg for unlocking one file but not familiar with unix enough to do what I'd like. Thanks! (0 Replies)
Discussion started by: alternapop
0 Replies

4. Shell Programming and Scripting

awk print: howto single quote not interpreted!?

cat a | awk -F";" '{print "update db set column=' "$2" ' where column1=\""$1"\";"}' > ip-add.sql Hi! I'm a new user! i need to use single quote in the double quotes print string The apex between che "$2" should not be interpreted, but....how?! I'm trying to use \ but don't work correctly! ... (4 Replies)
Discussion started by: Re DeL SiLeNziO
4 Replies

5. Shell Programming and Scripting

Print only Filename based on given String on file name

Hi, I am new to this unix world. Any ways, I would like to write a shell script that can print the file name. Ex : directory will have 5 files with different name.No matter what are contents are. Now I need to find the file which will have particular name (sub string ).Please do not... (5 Replies)
Discussion started by: akb2010
5 Replies

6. Shell Programming and Scripting

Print filename with awk

I can got the filename with this script. it's only show "-" in result. cut -d , -f7 CSV_d.* | awk 'OFS=":"{print FILENAME,substr($1,1,8),substr($1,9,2),substr($1,11,2),substr($1,13,2)}' | sort |uniq (2 Replies)
Discussion started by: before4
2 Replies

7. Shell Programming and Scripting

print all filenames in directory with path to another file

hi, i have a directory at /path/unix with the following files 1.txt 2.txt 3.txt 4.txt I want to make another file called filenames.txt at a different location called /path/home. So, my output file would be /path/home/filenames.txt with contents /path/unix/1.txt... (1 Reply)
Discussion started by: jacobs.smith
1 Replies

8. Shell Programming and Scripting

Use while loop to read file and use ${file} for both filename input into awk and as string to print

I have files named with different prefixes. From each I want to extract the first line containing a specific string, and then print that line along with the prefix. I've tried to do this with a while loop, but instead of printing the prefix I print the first line of the file twice. Files:... (3 Replies)
Discussion started by: pathunkathunk
3 Replies

9. Linux

How to print full path name along with file extension?

Hi I have a requirement like this: /abc/a/x.txt /abc/a/y.txt /abc/b/x.gz /abc/b/y.txt I need output like this: /abc/a:*.txt /abc/b:*.txt /abc/b:*.gz I have tried find /abc -type f -name "*.*" ||awk -F . '{print $NF}' it is print only extensions without path name. Please... (5 Replies)
Discussion started by: lijjumathew
5 Replies

10. Shell Programming and Scripting

How to print contents of file when the file path is in a variable?

The file f1 contains the text "body" (shell prompt is "$"): $ cat ~/path/f1 body How to print contents of f1 when the f1 path is in a variable? Here is my failed attempt: $ f1="~/path/f1" $ echo $f1 ~/path/f1 $ cat $f1 cat: '~/path/f1': No such file or directory (2 Replies)
Discussion started by: wolfv
2 Replies

LEARN ABOUT HPUX

zgrep

ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME

       zgrep - search possibly compressed files for a regular expression

SYNOPSIS

       zgrep [ grep_options ] [ -e ] pattern filename...

DESCRIPTION

       Zgrep  invokes  grep  on  compressed  or  gzipped  files.   These  grep	options  will  cause  zgrep  to  terminate  with  an  error  code:
       (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*).  All other options specified are passed directly to grep.  If no file is specified,  then  the
       standard input is decompressed if necessary and fed to grep.  Otherwise the given files are uncompressed if necessary and fed to grep.

       If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.

EXIT CODE

       2 - An option that is not supported was specified.

AUTHOR

       Charles Levert (charles@comm.polymtl.ca)

SEE ALSO

       grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)

																	  ZGREP(1)
All times are GMT -4. The time now is 11:11 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy