10-07-2009
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10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
i have hundreds of directories that have to be renamed. the directory structure is fairly uniform which makes the scripting a little simpler.
suppose i have many directories like this */*/*/*abc* (in other words i have similar directory names 3 dirs deep that all contain the pattern abc in... (8 Replies)
Discussion started by: quantumechanix
8 Replies
2. Shell Programming and Scripting
I am trying to use a loop to strip of the funny character ^M at the end of all lines in each file found in current directory and I have used the following in a script:
find . -type f -name '*.txt' | while read file
do
echo "stripping ^M from ..."
ex - "$file" > $tempfile
%s/^M//g
wq!
# mv... (4 Replies)
Discussion started by: bisip99
4 Replies
3. UNIX for Dummies Questions & Answers
I have a number of files in directories labeled like this:
/Data/tr_gray/tr_DTI/dti_FA.nii.gz
(the brackets here represent a range of number that the files are labeled with)
I need to rename each dti_FA.nii.gz file according to the name of the folder it resides in. For example, the file ... (3 Replies)
Discussion started by: tk0034
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4. Shell Programming and Scripting
Hi,
We have a file (e.g. a .csv file, but could be any other format), with 2 columns: the old value and the new value. We need to modify all the files within the current directory (including subdirectories), so find and replace the contents found in the first column within the file, with the... (9 Replies)
Discussion started by: Talkabout
9 Replies
5. Shell Programming and Scripting
Hi all,
I have a many folders with zipped files in them. The zipped files are txt files from different folders. The txt files have the same names. If i try to
find . -type f -name "*.zip" -exec cp -R {} /myhome/ZIP \; it fails since the ZIP files from different folders have the same names and... (2 Replies)
Discussion started by: pmkenya
2 Replies
6. UNIX for Dummies Questions & Answers
Hi,
I have a directory with a lot of files like this:
a.bam
b.bam
c.bam
I like to rename these files based on a list where the name of the files in the first column will be replasced by the names in the second column. Here is my list which is a tab-delimited text file:
a x
b y
c ... (4 Replies)
Discussion started by: a_bahreini
4 Replies
7. Shell Programming and Scripting
Hello, I have a text file "file.list" with the contents below.
file1
filename1
file2
filename2
file3
filename3
file1, file2 and file3 are files existing in the same directory as the text file file.list.
I want to rename file1 to filename1, file2 to filename2, as show in the text... (1 Reply)
Discussion started by: james2009
1 Replies
8. Shell Programming and Scripting
Hey guys,
I have wrote the following script to apply a module named "trinity" on my files. (it takes two input files and spit a trinity.fasta as output)
#!/bin/bash -l
#SBATCH -p node
#SBATCH -A <projectID>
#SBATCH -n 16
#SBATCH -t 7-00:00:00
#SBATCH --mem=128GB
#SBATCH --mail-type=ALL... (1 Reply)
Discussion started by: @man
1 Replies
9. UNIX for Beginners Questions & Answers
Hello!
New here although not completely new to Unix.
I wonder how I could rename files based on the data found in a simple textfile.
It goes like this:
I have 4 files
1 ldfgkkfjslkdfjsldkfjsf.wav
2 nndsdflksdjf.wav
3 sdflksjdf jjsdflsdfl.wav
4 dkadsdddd.wav
Textfile.txt looks like... (14 Replies)
Discussion started by: Oortone
14 Replies
10. UNIX for Beginners Questions & Answers
Hello Everyone ,
Iam a newbie to shell programming and iam reaching out if anyone can help in this :-
I have two files
1) Insert.txt
2) partition_list.txt
insert.txt looks like this :-
insert into emp1 partition (partition_name)
(a1,
b2,
c4,
s6,
d8)
select
a1,
b2,
c4, (2 Replies)
Discussion started by: nubie2linux
2 Replies
LEARN ABOUT DEBIAN
unparse_time
PARSE_TIME(3) BSD Library Functions Manual PARSE_TIME(3)
NAME
parse_time, print_time_table, unparse_time, unparse_time_approx, -- parse and unparse time intervals
LIBRARY
The roken library (libroken, -lroken)
SYNOPSIS
#include <parse_time.h>
int
parse_time(const char *timespec, const char *def_unit);
void
print_time_table(FILE *f);
size_t
unparse_time(int seconds, char *buf, size_t len);
size_t
unparse_time_approx(int seconds, char *buf, size_t len);
DESCRIPTION
The parse_time() function converts a the period of time specified in into a number of seconds. The timespec can be any number of <number
unit> pairs separated by comma and whitespace. The number can be negative. Number without explicit units are taken as being def_unit.
The unparse_time() and unparse_time_approx() does the opposite of parse_time(), that is they take a number of seconds and express that as
human readable string. unparse_time produces an exact time, while unparse_time_approx restricts the result to only include one units.
print_time_table() prints a descriptive list of available units on the passed file descriptor.
The possible units include:
second, s
minute, m
hour, h
day
week seven days
month 30 days
year 365 days
Units names can be arbitrarily abbreviated (as long as they are unique).
RETURN VALUES
parse_time() returns the number of seconds that represents the expression in timespec or -1 on error. unparse_time() and
unparse_time_approx() return the number of characters written to buf. if the return value is greater than or equal to the len argument, the
string was too short and some of the printed characters were discarded.
EXAMPLES
#include <stdio.h>
#include <parse_time.h>
int
main(int argc, char **argv)
{
int i;
int result;
char buf[128];
print_time_table(stdout);
for (i = 1; i < argc; i++) {
result = parse_time(argv[i], "second");
if(result == -1) {
fprintf(stderr, "%s: parse error
", argv[i]);
continue;
}
printf("--
");
printf("parse_time = %d
", result);
unparse_time(result, buf, sizeof(buf));
printf("unparse_time = %s
", buf);
unparse_time_approx(result, buf, sizeof(buf));
printf("unparse_time_approx = %s
", buf);
}
return 0;
}
$ ./a.out "1 minute 30 seconds" "90 s" "1 y -1 s"
1 year = 365 days
1 month = 30 days
1 week = 7 days
1 day = 24 hours
1 hour = 60 minutes
1 minute = 60 seconds
1 second
--
parse_time = 90
unparse_time = 1 minute 30 seconds
unparse_time_approx = 1 minute
--
parse_time = 90
unparse_time = 1 minute 30 seconds
unparse_time_approx = 1 minute
--
parse_time = 31535999
unparse_time = 12 months 4 days 23 hours 59 minutes 59 seconds
unparse_time_approx = 12 months
BUGS
Since parse_time() returns -1 on error there is no way to parse "minus one second". Currently "s" at the end of units is ignored. This is a
hack for English plural forms. If these functions are ever localised, this scheme will have to change.
HEIMDAL
October 31, 2004 HEIMDAL