guys,
my requirment goes like this:
I have a file, and wish to filter out records where
1. The first letter is o or O
and
2. The next 4 following letter should not be ther
I do not wish to use pipe and wish to do it in one shot.
The best expression I came up with is:
grep ^*... (10 Replies)
When i do ls -ld RT_BP* i am getting the following list.
drwxrwx--- 2 user group 256 Oct 17 10:09 RT_BP809
drwxrwx--- 2user group 256 Oct 17 10:09 RT_BP809.O
drwxrwx--- 2 user group 256 Oct 17 10:09 RT_BP810
drwxrwx--- 2user group 256 Oct... (2 Replies)
Hi, guys. I have one question, hope somebody can give me a hand
I have a file called passwd, the contents of it arebelow:
***********************
...
goldsimj:x:5008:200:
goldsij2:x:5009:200:
whitej:x:5010:201:
brownj:x:5011:202:
goldsij3:x:5012:204:
greyp:x:5013:203:
...... (6 Replies)
Hi,
I am executing a svnlook command to check to see if the following line exists. I need a regular expression to represent the line.
A /test/test1/qa/test2/index.html
A /test/test1/qa/test3/test.jpg
A /test/test1/qa/test3/test1.jpg
A /test/test1/qa/test4/test.swf
I just need to extract... (9 Replies)
Hello,
How to print the field separator in awk? please see the following code:
cat a.txt
a 1s 2s 3s 4s
b 2s 4s
$ awk 'BEGIN{FS==" "} {print $2 $3 }' te
1s2s
2s4s
I want to get the following output :
1s 2s
2s 4s
How to realize this ?
$ cat te
a 1s,,2s 3s ... (11 Replies)
Hi all,
How am I read a file, find the match regular expression and overwrite to the same files.
open DESTINATION_FILE, "<tmptravl.dat" or die "tmptravl.dat";
open NEW_DESTINATION_FILE, ">new_tmptravl.dat" or die "new_tmptravl.dat";
while (<DESTINATION_FILE>)
{
# print... (1 Reply)
Hi ,
I have few lines like
A20120101.ANU.ZIP
A20120401.ABC.ZIP
A20120105.KJK.ZIP
A20120809.JUG.ZIP
A20120101.MAT.ZIP
B20120301.ANU.XIP
I want to filter by
1. Files starting with A and Ending With Z ( ^A.*.ZIP$)
2. And either ANU, or KJK or MAT in the file name.
Hope my... (6 Replies)
Hello,
one step in a shell script i am writing, involves Grep command to search a regular expression in a line an only print the string after the match
an example line is below
/logs/GRAS/LGT/applogs/lgt-2016-08-24/2016-08-24.8.log.zip:2016-08-24 19:12:48,602 ERROR... (9 Replies)
I want to track only below:
I am using below, but it doesn't work: (6 Replies)
Discussion started by: proactiveaditya
6 Replies
LEARN ABOUT MINIX
grep
GREP(1) General Commands Manual GREP(1)NAME
grep - search a file for lines containing a given pattern
SYNOPSIS
grep [-elnsv] pattern [file] ...
OPTIONS -e-e pattern is the same as pattern
-c Print a count of lines matched
-i Ignore case
-l Print file names, no lines
-n Print line numbers
-s Status only, no printed output
-v Select lines that do not match
EXAMPLES
grep mouse file # Find lines in file containing mouse
grep [0-9] file # Print lines containing a digit
DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions
accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1
occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a
match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is
returned.
SEE ALSO cgrep(1), fgrep(1), sed(1), awk(9).
GREP(1)