09-30-2009
creating a command and sorting???
How do you write a command line that displays the number of files in the working directory with names that end with the letter S? Thanks
---------- Post updated at 09:34 PM ---------- Previous update was at 09:33 PM ----------
for unix sorry
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LEARN ABOUT HPUX
list_directory
list directory(1m) list directory(1m)
NAME
list directory - Displays a list of all the directories whose names match the specified directory name
SYNOPSIS
cdscp list directory directory-name [with attribute-name = attribute-value]
ARGUMENTS
The full name of a specific directory. The last simple name can contain wildcard characters. The name of a particular attribute. The
value of a particular attribute.
DESCRIPTION
The list directory command displays a list of all the directories whose names match the specified directory name. The last simple name can
contain wildcards. You can use a with attribute-name = attribute-value clause to limit output only to directories whose attributes have
values equal to the specified values. A space must precede and follow the = (equals sign).
Privilege Required
You must have read permission to the parent directory. If you use a with attribute-name = attribute-value clause in the command, you also
need read or test permission to the selected directories.
NOTE
This command is replaced at Revision 1.1 by the dcecp command and may not be provided in future releases of DCE.
EXAMPLE
The following command displays the names of all the directories in the /.:/sales directory: cdscp> list directory /.:/sales/*
LIST
DIRECTORY /.../abc.com/sales
AT 1991-10-15-15:43:58 atlanta austin boston chicago ontario ny seattle
RELATED INFORMATION
Commands: add directory(1m), create directory(1m), delete directory(1m), remove directory(1m), set directory(1m), set directory to
skulk(1m), show directory(1m)
list directory(1m)