thanks
but hardest thing is
i need to put it in a random place of the line
and i need to put it twice or three times in 1 line
and it should be like 5-10 words after the beginning or previous one
i did it like that:
but i'm pretty sure there's shorter way..
can someone tell me how can I insert a word in front of each line in a file.
i tried with sed but didn't managed yet.
Is there another command or this one(sed) works?
10x anyway. (7 Replies)
Hello all
im doing simple parsing on text file , but now I need to insert
string before the first line of the text file , how can I do that in perl? (3 Replies)
Greetings.
I am struggling with a shell script to make my life simpler, with a number of practical ways in which it could be used. I want to take a standard text file, and pull the 'n'th word from each line such as the first word from a text file.
I'm struggling to see how each line can be... (5 Replies)
Hi folks,
have a look into the attachment, i am not familiar with unix, can you please help me in this regard.
thanks in advance, :)
regards,
Geeko (4 Replies)
Hi All,
I have a file like this,
data1,data2,,,data5,data6.
i want to write a shell script to replace data3 with "/example/string". which means my data file should look like this .
data1,data2,example/string],,data5,data6.
Could you guys help me to get a sed command or any other command... (8 Replies)
FOLKS ,
i have a text file that is generated automatically of an another korn shell script, i want to bring in the fifth line of the text file in to my korn shell script and look for a particular word in the line . Can you all share some thoughts on this one.
thanks...
Venu (3 Replies)
Hi, Perl is new to me. I am trying to insert a line to a file.
Example: I have a file (trial.txt), content:
ZZZZ
AAA
DDDD
I am trying to insert CCC below AAA.
MY perl command:
open (FILE,"+>>C:\\Documents and Settings\\trial.txt\n")|| die "can't open file";
while(<FILE>)
{ ... (6 Replies)
HI,
I have a text file in which I have removed all new lines as I would like to introduce a new line at the end of each record in the file. There is no common end line for all the records. A new record will start by *RECORD*. So I want to introduce a new line before this line *RECORD*. So Can... (2 Replies)
Hello,
I am looking to automate a task - which is updating an existing access control instruction of a server and making sure that the attributes defined in the instruction is in sorted order. The instructions will be of a specific syntax.
For example lets assume below listed is one of an... (6 Replies)
Discussion started by: sanjayroc
6 Replies
LEARN ABOUT BSD
expr
EXPR(1) General Commands Manual EXPR(1)NAME
expr - evaluate arguments as an expression
SYNOPSIS
expr arg ...
DESCRIPTION
The arguments are taken as an expression. After evaluation, the result is written on the standard output. Each token of the expression is
a separate argument.
The operators and keywords are listed below. The list is in order of increasing precedence, with equal precedence operators grouped.
expr | expr
yields the first expr if it is neither null nor `0', otherwise yields the second expr.
expr & expr
yields the first expr if neither expr is null or `0', otherwise yields `0'.
expr relop expr
where relop is one of < <= = != >= >, yields `1' if the indicated comparison is true, `0' if false. The comparison is numeric if
both expr are integers, otherwise lexicographic.
expr + expr
expr - expr
addition or subtraction of the arguments.
expr * expr
expr / expr
expr % expr
multiplication, division, or remainder of the arguments.
expr : expr
The matching operator compares the string first argument with the regular expression second argument; regular expression syntax is
the same as that of ed(1). The (...) pattern symbols can be used to select a portion of the first argument. Otherwise, the
matching operator yields the number of characters matched (`0' on failure).
( expr )
parentheses for grouping.
Examples:
To add 1 to the Shell variable a:
a=`expr $a + 1`
To find the filename part (least significant part) of the pathname stored in variable a, which may or may not contain `/':
expr $a : '.*/(.*)' '|' $a
Note the quoted Shell metacharacters.
SEE ALSO sh(1), test(1)DIAGNOSTICS
Expr returns the following exit codes:
0 if the expression is neither null nor `0',
1 if the expression is null or `0',
2 for invalid expressions.
7th Edition April 29, 1985 EXPR(1)