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Full Discussion: Script to extract line from logfile
Top Forums Shell Programming and Scripting Script to extract line from logfile Post 302354486 by jp2542a on Friday 18th of September 2009 09:47:45 AM
Old 09-18-2009
awk is your friend :D
This is how you do it using awk.

This will create a files based on the input file names. The file without the lines you want removed will be <filename>.strip . The file with the lines removed will be <filename>.sav . <filename> is the path to the input file.

First make a file containing the awk code. I used log.awk for the example.

Code:
# strip lines out of file and make log of lines removed
# clause to make file name for output
(FNR == 1) {                    # check if first line of new file
        if ( NR != 1)           # see if this is not first file
        {
                close(FILEOUT)  # if true, then we close previous files
                close(FILELOG)
        }
        FILEOUT = FILENAME ".strip"     # create striped file name using input file name
        FILELOG = FILENAME ".sav"       # create file name for removed lines
}

# clause for ever line
{
        if ( $0 !~ /ntp/ )      # replace ntp with your pattern
                print > FILEOUT # save to stripped file if pattern not found
        else
                print > FILELOG # save to remove log if pattern match
}

Change the pattern to whatever you want to use. (GuestUser?)

Then execute it using:

Code:
awk -f log.awk <list of files>

Where <list of files> is a bunch of files you want to process. You get a set of .sav and .strip files in the same directory as the source file.

Note: I don't believe in modifying source files when not necessary. Tools such as this should not modify input files.

If for some reason you want to do the same thing in a single line, use this format:

Code:
awk '(FNR == 1) { if ( NR != 1) { close(FILEOUT); close(FILELOG) } FILEOUT = FILENAME ".strip"; FILELOG = FILENAME ".sav" } { if ( $0 !~ /YOUR-PATTERN-HERE/ ) print > FILEOUT; else print > FILELOG }' <list-of-files>

 

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LEARN ABOUT XFREE86

filelog

FILELOG(5)							AFS File Reference							FILELOG(5)

NAME
       FileLog - Traces File Server operations

DESCRIPTION
       The FileLog file records a trace of File Server (fileserver process) operations on the local machine and describes any error conditions it
       encounters.

       If the FileLog file does not already exist in the /var/log/openafs directory when the File Server starts, the server process creates it and
       writes initial start-up messages to it. If there is an existing file, the File Server renames it to FileLog.old, overwriting the existing
       FileLog.old file if it exists.

       The file is in ASCII format. Administrators listed in the /etc/openafs/server/UserList file can use the bos getlog command to display its
       contents. Alternatively, log onto the file server machine and use a text editor or a file display command such as the UNIX cat command. By
       default, the mode bits on the FileLog file grant the required "r" (read) permission to all users.

       The File Server records operations only as it completes them, and cannot recover from failures by reviewing the file. The log contents are
       useful for administrative evaluation of process failures and other problems.

SEE ALSO
       UserList(5), bos_getlog(8), fileserver(8)

COPYRIGHT
       IBM Corporation 2000. <http://www.ibm.com/> All Rights Reserved.

       This documentation is covered by the IBM Public License Version 1.0.  It was converted from HTML to POD by software written by Chas
       Williams and Russ Allbery, based on work by Alf Wachsmann and Elizabeth Cassell.

OpenAFS 							    2012-03-26								FILELOG(5)
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