in my script i want to get the month part of date. I need the month part because i will grep logs every month using it. When i run the "date" command i got the below result:
but when i type the below command i got Aug24 without space between "Aug" and "24" :
How can i get a result as same as "Aug 24".
Hello all:
Running SunOS 5.6 on a SPARCstation-5...and using bourne shell.
This is a line from a script I am writing:
LOG=/opt/msplib/sys/logs/alarm.log$*
grep "Call Answered" $LOG |wc -l | awk '{ print "Call Answered\t" $1 "\tIVR\t" "AR-a"}
It works great, and produces the... (5 Replies)
Hi,
Can anyone tell me how can we assign a system date to a variable in awk script? Also how can we use this varible to print this in an other file.
Regards,
Jamuna (13 Replies)
i'm facing problems in using system date in a awk script...
it should display the date in a report in mm/dd/yy format..
please help me in this case..
thanks (3 Replies)
i want to use awk to print the first,second and add date as third column in a file
awk -F"|" ' { print $1,$2,current date }' tom.unl >> top.txt
how can i achieve this,i need the comma's to seperate them and finally print current date and time as the third.
i want output like... (5 Replies)
Hi,
I want to print the number of lines of a file along with filename and today's date.
Ex:
XXX|07-22-2010|8
I am using as
wc -c -l file.txt | awk '{print "XXX|",date +"%m-%d-%Y","|",$1}'
But this one prints as
AAA| 0 | 8
Can anyone please help me on this for printing the date?
... (3 Replies)
can any1 explain me hw is below wrking:
wat is substr and dd,mmyear used for
wat values will go in dese?
sdt='31122010235959'
sdate=`validate_date $sdt`
validate_date()
{
dt="$1"
set `echo $dt | nawk '{ print... (2 Replies)
Hi All....
I need to pass date into awk and parse logfile based on that.... i used both awk and /usr/xpg4/bin/awk... both are throwing up error.....
So here is the stuff...
when i use /usr/xpg4/bin/awk :
DATE=`date '+%Y %b %d'`
START=00
END=23
/usr/xpg4/bin/awk -v DATE={"$DATE"} -v... (3 Replies)
Hi all,
Need an urgent help on the below scenario.
script:
awk -F","
'BEGIN { #some variable assignment}
{ #some calculation and put values in array}
END {
year=#getting it from array and assume this will be 2014
month=#getting it from array and this will be 05
date=#... (7 Replies)
current date command runs well
awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
subtract 30 days fails
awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Hey everyone,
I'm trying to create a script using awk and if that will list all of our aws tapes that have archived date that is past 90 days from todays current date, so that I can pass that to my aws command to remove.
The fifth column is the creation date in epoch/seconds, so I'm... (13 Replies)
Discussion started by: beyondmondays
13 Replies
LEARN ABOUT OPENSOLARIS
sulog
sulog(4) File Formats sulog(4)NAME
sulog - su command log file
SYNOPSIS
/var/adm/sulog
DESCRIPTION
The sulog file is a record of all attempts by users on the system to execute the su(1M) command. Each time su(1M) is executed, an entry
is added to the sulog file.
Each entry in the sulog file is a single line of the form:
SU date time
result port user-newuser
where
date The month and date su(1M) was executed. date is displayed in the form mm/dd where mm is the month number and dd is the day
number in the month.
time The time su(1M) was executed. time is displayed in the form HH/MM where HH is the hour number (24 hour system) and MM is the
minute number.
result The result of the su(1M) command. A ` + ' sign is displayed in this field if the su attempt was successful; otherwise a ` - '
sign is displayed.
port The name of the terminal device from which su(1M) was executed.
user The user id of the user executing the su(1M) command.
newuser The user id being switched to with su(1M).
EXAMPLES
Example 1 A sample sulog file.
Here is a sample sulog file:
SU 02/25 09:29 + console root-sys
SU 02/25 09:32 + pts/3 user1-root
SU 03/02 08:03 + pts/5 user1-root
SU 03/03 08:19 + pts/5 user1-root
SU 03/09 14:24 - pts/5 guest3-root
SU 03/09 14:24 - pts/5 guest3-root
SU 03/14 08:31 + pts/4 user1-root
FILES
/var/adm/sulog su log file
/etc/default/su contains the default location of sulog
SEE ALSO su(1M)SunOS 5.11 6 Jun 1994 sulog(4)