Hi Please help me out with this problem:
I want to have a script that would change the nth field seperator in a line into something else.
like
a,d,4,2,97,8,9
into
a,d,4,2,97/8/9
Thanks (2 Replies)
I have a line like this:
I want to move HTTP/1.1 200 OK to the next line and put a blank line between the two lines i.e.
How can i get it using awk?
Thanks in advance (2 Replies)
from this input
WEBELSOLAR,29122009,1:1
WIPRO,15062010,2:3
ZANDUREALT,18012007,1:3
i want output as
WEBELSOLAR,20091229,1:1
WIPRO,20100615,2:3
ZANDUREALT,20070118,1:3
basically input is in ddmmyyyy format and i was to convert it to yyyymmdd format (1 Reply)
Hello,
I have the following example data file:
Rv.Global_Sk,1077.160523,D,16/09/2011
Rv.Global_Sk,1077.08098,D,17/09/2011
Rv.Global_Sk,1077.001445,D,18/09/2011
Rv.Global_Sk,1072.660733,D,19/09/2011
Rv.Global_Sk,1070.381557,D,20/09/2011
Rv.Global_Sk,1071.971747,D,21/09/2011... (4 Replies)
Hi guys, i have an executable file that contains several records and fields. One of the records has a variable filed that must be changed each time i want to execute the file. Would it be possible that i can use a loop to change the value of that field? Suppose that the field address is:
Record... (5 Replies)
Hi !
input:
111|222|333|aaa|bbb|ccc
999|888|777|nnn|kkk
444|666|555|eee|ttt|ooo|ppp
With awk, I am trying to change the FS "|" to "; " only from the 4th field until the end (the number of fields vary between records).
In order to get:
111|222|333|aaa; bbb; ccc
999|888|777|nnn; kkk... (1 Reply)
Hello,
I have a file with a date field with various lengths. For example:
m/d/yyyy hh:mm or h:mm
mm/dd/yyyy hh:mm or h:mm
Is there a way using sed or awk to change the field to m/d/y ? I don't need the hours and minutes in that field, just the date in the proper format.
Thanks in... (6 Replies)
In the awk below I am trying to copy the entire contents of $6 there may be multiple values seperated by a ;, to $8, if $8 is . (lines 1 and 3 are examples). If that condition $8 is not . (line2 is an example) then that line is skipped and printed as is. The awk does execute but prints the output... (3 Replies)
I am trying to use awk to check if each $2 in file1 falls between $2 and $3 of the matching $4 line of file2. If it does then in $5 of file2, exon if it does not intron. I think the awk below will do that, but I am struggling trying to is add a calculation that if the difference is less than 10,... (27 Replies)
Discussion started by: cmccabe
27 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)