The variable has a capital F and the grep command doesn't:
It hasn't gone into an infinite loop... it's just waiting for input because $logfile is blank the shell evaluates that to nothing (not a filename as you thought).
Is there a way to grep for something and then print out 10 lines after it.
for example if I want to grep for a word, then output the following 10 or whatever number of lines after the word. (5 Replies)
Using shell scripts, I use grep to find the word “error” in a log file:
grep error this.log.
How can I print or get the line 3 lines below the line that word “error” is located?
Thanks in advance for your response. (9 Replies)
I found another problem with my disk-adding script today. When looking for disks, I use grep.
When I grep for the following disk sizes:
5242880
I also pick up these as well:
524288000
How do I specifically pick out one or the other, using grep, without resorting to the -v option?
... (9 Replies)
Hi All,
I have a log file and I want to parse the logfile with a script.A sample text is shown below:
I would grep on "return code " on this file. Any idea how the lines above and below the grep patterns could also be extracted.
Thanks!
nua7
The runLoggingInstall return code is 0... (3 Replies)
Hello,
I would like for the user to input the date for a particular log file, then have the input sent to a variable, which is then used via grep to extra the logs for the specific date the user request.
I did some searching, but I still don't understand why I'm not seeing any result.
... (4 Replies)
I have a list of fields that I want to check a file for, returning that field if it not found at all in the file. Is there a way to do a grep -lc and return the passed variable too rather then just the count?
I am doing some crappy work-around now but I was not sure how to regrep this for :0 so... (3 Replies)
I have a script which reads a number out of a log file. The pertinent line is this:
cat /tmp/listofnumbers
When I run cat /tmp/listofnumbers what I am seeing is on each line.
I am trying to make the script read from that file and grep for a variable like the following line should do:
... (4 Replies)
Hi All,
When i am logged into a server , i am able to assign grep value to a variable as follows.
VAR=`grep 'Listener stopped' /logs/perf.log`
However, when i log out of the server, and try to execute the following command by first SSHing into server, it throws error.
$ VAR=`ssh Server... (4 Replies)
I have a lot of files with keywords and unique names. I'm using a shell script to refer to a simple pattern file with comma separated values in order to match on certain keywords. The problem is that I don't understand how to handle the wildcard values when I want to skip over the unique names.
... (5 Replies)
Im trying to search for a single variable in the first field and from that output use awk to extract out the lines that contain a value less than a value stored in another variable. Both the variables are associated with each other.
Any guidance is appreciated.
File that contains the... (6 Replies)
Discussion started by: ncwxpanther
6 Replies
LEARN ABOUT MINIX
zgrep
ZGREP(1) General Commands Manual ZGREP(1)NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)ZGREP(1)