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Full Discussion: Not able to assign a value to variable
Top Forums Shell Programming and Scripting Not able to assign a value to variable Post 302336341 by Amey Joshi on Tuesday 21st of July 2009 11:36:02 PM
Old 07-22-2009
Question Not able to assign a value to variable
Hi Experts,

I am facing some problem while developing the script.My input config.csv file contains the three columns namely pathname,filename,filetype.Based on the file type i have to use ftp command that is if filetype=csv then do ftp.
The input file is

HTML Code:
cat config.csv
pathname,filename,filetype
/home/fir/dir,filename1,csv
/home/fir1/dir,filename2,csv
/home/fir4/dir,filename3,csv
/home/fir/dir6,filename4,dat
To achieve this i have developed the following script:
HTML Code:
#!/bin/ksh
head -5 config.csv | while read line
do
Type1=`echo $line | awk -F"," '{print $3}'`
Type=`echo $Type1 | tr [A-Z] [a-z]`
if [ $Type == 'csv' ]
 then
   DataFileName=`echo $line | awk -F"," '{print $2}'`
   DataPath=`echo $line| awk -F"," '{print $1}'`
   echo $DataPath
   slash=`echo '\'`
   filelocation=`echo $DataPath$slash$DataFileName`
   echo do sftp -n
fi
done
Now the problem is that the value of DataPath variable is coming as
HTML Code:
echo $DataPath
homefirdir
Some how the slashes are getting removed.Smilie
How can we achieve the variable value as '/home/fir/dir ' and pass it to ftp command?

Thanks in Advance!
 

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LEARN ABOUT PHP

opendir

OPENDIR(3)								 1								OPENDIR(3)

opendir - Open directory handle

SYNOPSIS

       resource opendir (string  $path, [resource  $context])

DESCRIPTION

	Opens up a directory handle to be used in subsequent closedir(3), readdir(3), and rewinddir(3) calls.

PARAMETERS

	      o $path
		- The directory path that is to be opened

	      o $context
		- For a description of the $context parameter, refer to the streams section of the manual.

RETURN VALUES

	Returns a directory handle resource on success, or FALSE on failure.

	If  $path  is  not  a  valid  directory or the directory can not be opened due to permission restrictions or filesystem errors, opendir(3)
       returns FALSE and generates a PHP error of level  E_WARNING. You can suppress the error output of opendir(3) by prepending '@' to the front
       of the function name.

CHANGELOG

       +--------+---------------------------------------------------+
       |Version |						    |
       |	|						    |
       |	|		     Description		    |
       |	|						    |
       +--------+---------------------------------------------------+
       | 5.0.0	|						    |
       |	|						    |
       |	|      $path supports the ftp:// URL wrapper.	    |
       |	|						    |
       | 4.3.0	|						    |
       |	|						    |
       |	| $path  can  also be any URL which supports direc- |
       |	| tory listing, however only the file:// URL  wrap- |
       |	| per supports this in PHP 4			    |
       |	|						    |
       +--------+---------------------------------------------------+
EXAMPLES

       Example #1

	      opendir(3) example

	      <?php
	      $dir = "/etc/php5/";

	      // Open a known directory, and proceed to read its contents
	      if (is_dir($dir)) {
		  if ($dh = opendir($dir)) {
		      while (($file = readdir($dh)) !== false) {
			  echo "filename: $file : filetype: " . filetype($dir . $file) . "
";
		      }
		      closedir($dh);
		  }
	      }
	      ?>

	      The above example will output something similar to:

	      filename: . : filetype: dir
	      filename: .. : filetype: dir
	      filename: apache : filetype: dir
	      filename: cgi : filetype: dir
	      filename: cli : filetype: dir

SEE ALSO

       is_dir(3), readdir(3), dir(3).

PHP Documentation Group 														OPENDIR(3)
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