Hi Gurus,
We have a ftpserver from which we do a dir command and output it to a local file.
The content of the ftpfile is:
I generally use awk '{print $4}' ftpfile. But, I realized that the filename in the ftp might contain spaces.
So I came up with the command:
But the above command prints new line for every print I give. I want it in the same line. I tried using cut but it doesn't help.
On an ad-hoc basis, I am currently using the below command:
awk '{if (NF!=4) {print $4,$NF}else {print $4}}' ftplist
The above command prints what I want but, I assume here that the filename will have only one space.
Please suggest.
Hi,
I am currently confused.
Suppose I have a file something like the one below.
4299|raj Telecommunications|12|||||
4302|anjali International Ltd.|86|ritchie||dong|(000)2890 9993 |(222)4881 3689
4305|フィデュシアリ・ト-スト・インター...ショ...ル投資顧問株式会社 |112||||01-9211-1931 |08-3677-1985
Now... (2 Replies)
hi i have a file with content, i need to extract last column from each line including spaces and form a string
i used echo "$LINE" | awk '{print $1,$2}' | grep '^\ 33333030 30303030 30303030 CTL1330000000000
44453932 33353237 36333030 0000DE9235276300
30305453 30353934 44453932... (4 Replies)
How to manipulate first column and reverse the line order in third and fourth column as follws?
For example i have a original file like this:
file1
0.00000000E+000 -1.17555359E-001 0.00000000E+000
2.00000000E-002 -1.17555359E-001 0.00000000E+000
... (1 Reply)
Hi All,
If anybody could help me with my scenario here. I have a statement file. Example of some content:
DATE DESC Debit Credit Total Rate
02-Jan-08 Lodgement 200.00 1200.00 2.51
14-Sep-07 Withdrawal 50.00 1000.00 ... (8 Replies)
BAQ001 /dev/rdsk/c2t0d7 1C13 (M) RW 69053
The line above is from a text file. I want to use awk to extract the value in the third column 1C13.
I just can't seem to get the syntax right or something. Any help would be appreciated.
Thanks, (5 Replies)
Hi friends,
My input file is this way
chr1 100 200 "abc"
chr1 350 400 "abc"
chr2 450 600 "def"
chr2 612 780 "def"
How do I make this file into
chr1 100 400 "abc"
chr2 450 780 "def"
This is basically matching on the fourth column and taking the minimum of second column and the... (4 Replies)
I have a file as follows
ATOM 5181 N AMET K 406 12.440 6.552 25.691 0.50 7.37 N
ATOM 5182 CA AMET K 406 13.685 5.798 25.578 0.50 5.87 C
ATOM 5183 C AMET K 406 14.045 5.179 26.909 0.50 5.07 C
ATOM 5184 O MET K... (14 Replies)
Hi Experts,
I am new to UNIX. One of my file records are like below
220 IN C/A 515013 NULL NULL
220 IN C/A 515017 NULL NULL
225 IN C/A 333701 NULL NULL
225 IN C/A 515034 NULL NULL
225 IN C/A 499201 NULL NULL
225 IN C/A 499202 NULL NULL
The above mentioned records delimiter is... (4 Replies)
Hi have a large spreadsheet which has 4 columns
APM00111803814 server_2 96085 Corp IT Desktop and Apps
APM00111803814 server_2 96085 Corp IT Desktop and Apps
APM00111803814 server_2 96034 Storage Mgmt Team
APM00111803814 server_2 96152 GWP... (6 Replies)
Discussion started by: kieranfoley
6 Replies
LEARN ABOUT POSIX
zipgrep
ZIPGREP(1) General Commands Manual ZIPGREP(1)NAME
zipgrep - search files in a ZIP archive for lines matching a pattern
SYNOPSIS
zipgrep [egrep_options] pattern file[.zip] [file(s) ...] [-x xfile(s) ...]
DESCRIPTION
zipgrep will search files within a ZIP archive for lines matching the given string or pattern. zipgrep is a shell script and requires
egrep(1) and unzip(1) to function. Its output is identical to that of egrep(1).
ARGUMENTS
pattern
The pattern to be located within a ZIP archive. Any string or regular expression accepted by egrep(1) may be used. file[.zip] Path
of the ZIP archive. (Wildcard expressions for the ZIP archive name are not supported.) If the literal filename is not found, the
suffix .zip is appended. Note that self-extracting ZIP files are supported, as with any other ZIP archive; just specify the .exe
suffix (if any) explicitly.
[file(s)]
An optional list of archive members to be processed, separated by spaces. If no member files are specified, all members of the ZIP
archive are searched. Regular expressions (wildcards) may be used to match multiple members:
* matches a sequence of 0 or more characters
? matches exactly 1 character
[...] matches any single character found inside the brackets; ranges are specified by a beginning character, a hyphen, and an end-
ing character. If an exclamation point or a caret (`!' or `^') follows the left bracket, then the range of characters within
the brackets is complemented (that is, anything except the characters inside the brackets is considered a match).
(Be sure to quote any character that might otherwise be interpreted or modified by the operating system.)
[-x xfile(s)]
An optional list of archive members to be excluded from processing. Since wildcard characters match directory separators (`/'),
this option may be used to exclude any files that are in subdirectories. For example, ``zipgrep grumpy foo *.[ch] -x */*'' would
search for the string ``grumpy'' in all C source files in the main directory of the ``foo'' archive, but none in any subdirectories.
Without the -x option, all C source files in all directories within the zipfile would be searched.
OPTIONS
All options prior to the ZIP archive filename are passed to egrep(1).
SEE ALSO egrep(1), unzip(1), zip(1), funzip(1), zipcloak(1), zipinfo(1), zipnote(1), zipsplit(1)URL
The Info-ZIP home page is currently at
http://www.info-zip.org/pub/infozip/
or
ftp://ftp.info-zip.org/pub/infozip/ .
AUTHORS
zipgrep was written by Jean-loup Gailly.
Info-ZIP 20 April 2009 ZIPGREP(1)