I'm having problems since few days ago, and i'm not able to make it works with a simple awk+grep script (or other way to do this).
For example, i have a input file1.txt:
cat inputfile1.txt
218299910417
1172051195
1172070231
1172073514
1183135117
1183135118
1183135119
1281440202
... (3 Replies)
Hi all,
Is it possible for grep to output just the pattern match and not the whole line when it comes across a match? I know you can adjust the number of trailing or leading lines that are printed, but am yet to find anything that outputs just the pattern match.
Cheers,
Tim (5 Replies)
Hi,
i would like to get the above and below lines of the grep pattern .
For ex :
file as below:
chk1- aaaa
1-Nov
chk2 -aaaa
##########
chk1-bbbbbb
1-Nov
chk2-bbbbbb
#########
my search pattern is date : 1-Nov
i need the o/p as below
chk1- aaaa
1-Nov (6 Replies)
how to use "awk" to print any record has pattern not equal ? for example my file has 5 records & I need to get all lines which $1=10 or 20 , $2=10 or 20 and $3 greater than "130302" as it shown :
10 20 1303252348212B030
20 10 1303242348212B030
40 34 1303252348212B030
10 20 ... (14 Replies)
Hi,
Do anybody know how to print out only those record that column 1 is "a" , then followed by "b"?
Input file :
a comp92 2404242 2405172
b comp92 2405303 2406323
b comp92 2408786 2410278
a comp92 2410271 2410337
a comp87 1239833 1240418
b comp87... (3 Replies)
Hi all,
I am struck with the below requirement. I need to grep a particular pattern in a file and then print next n lines of it for further processing.
I have used the below code
grep -A 3 "pattern" filename
But it is throwing error as below.
grep: illegal option -- A
Can... (14 Replies)
Hi,
I need help on a complicated file that I am working on. I wanted to extract important info from a very huge file. It is space delimited file. I have hundred thousands of records in this file. An example content of the inputfile as below:-
##
ID Ser402 Old; 23... (2 Replies)
Discussion started by: redse171
2 Replies
LEARN ABOUT OSX
svk::log::filter::grep
SVK::Log::Filter::Grep(3) User Contributed Perl Documentation SVK::Log::Filter::Grep(3)SYNOPSIS
SVK::Log::Filter::Grep - search log messages for a given pattern
DESCRIPTION
The Grep filter requires a single Perl pattern (regular expression) as its argument. The pattern is then applied to the svn:log property
of each revision it receives. If the pattern matches, the revision is allowed to continue down the pipeline. If the pattern fails to
match, the pipeline immediately skips to the next revision.
The pattern is applied with the /i modifier (case insensitivity). If you want case-sensitivity or other modifications to the behavior of
your pattern, you must use the "(?imsx-imsx)" extended pattern (see "perldoc perlre" for details). For example, to search for log messages
that match exactly the characters "foo" you might use
svk log --filter "grep (?-i)foo"
However, to search for "foo" without regards for case, one might try
svk log --filter "grep foo"
The result of any capturing parentheses inside the pattern are not available. If demand dictates, the Grep filter could be modified to
place the captured value somewhere in the stash for other filters to access.
If the pattern contains a pipe character ('|'), it must be escaped by preceding it with a '' character. Otherwise, the portion of the
pattern after the pipe character is interpreted as the name of a log filter.
STASH /PROPERTY MODIFICATIONS
Grep leaves all properties and the stash intact.
perl v5.10.0 2008-08-04 SVK::Log::Filter::Grep(3)