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Top Forums Shell Programming and Scripting Getting 15 characters after search phrase Post 302332150 by bfr on Wednesday 8th of July 2009 08:36:59 AM
Old 07-08-2009
Getting 15 characters after search phrase

I have data that looks like this:

Code:
2002  140  40800.0060  GPS 20  C1  25477810.2305
2002  140  41100.0060  GPS 20  C1  25298056.0453

I need to get data after certain pattern.. for example if i search for C1
it should return

Code:
25477810.2305
25298056.0453

To achieve this, it should:

1) In the best scenario, if possible, it would start after the space/spaces that come after the search word, print the characters, and stop when space is found again

2) if that is not possible, other way would be to return 15 characters after the search pattern(after = the pattern itself would be excluded).

I tried with grep and sed, but could not get the results i wanted..

Thank you in advance!
 

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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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