Thx blitzer for the reply, what if I want to count files updated ona specfic date.
I mean, I don't want to count all the files in the directory. I want to count files updated/created on a specfic date (say today 08-07-2009).
An equivalent in bash is some thing like this:
This is how I can count files, updated on 8th july 2009 (using bash)
Hello!!
I have directories from 2008, with files in them. I want to create a script that will find the directoried from 2008 (example directory:
drwxr-xr-x 2 isplan users 1024 Nov 21 2008 FILES_112108), delete the files within those directories and then delete the directories... (3 Replies)
Hi, I am a unix newbie.I need to write a shell script to move my oracle READ WRITE datafiles from one serevr to another. I need to move it from /u01/oradata/W1KK/.. to /u01/oradata/W2KK,
/u02/oradata/W1KK/.. to /u02/oradata/W2KK.
That is, I actaully am moving my datafiles from one database to... (2 Replies)
Can someone please guide me how I can get a single line for each directory:
ls -ltrR|awk '/(\.\/)()*/ { print $0;d=$0;n=0;} /^-*/ { n=n+1; print d,n } '
What I'm trying to get is
webconsole: 23
logs: 34
logd: 344
Regards,
BB (3 Replies)
I am very new to unix as well as shell scripting.
I have to write a script for the following requirement. In have to list all the files in directory and its sub directories along with file path and size of the file
Please help me in this regard and many thanks in advance. (3 Replies)
Hi
I need to count files in current directory, except file abc.txt, if it exists
I have such script:
FILES_COUNT=$(find * -name "*" | wc -l)
but it counts all files. I need to exclude abc.txt (5 Replies)
Dear Members,
I have a list of xml files like
abc.xml.table
prq.xml.table
...
..
.
in a txt file.
Now I have to search the file(s) in all directories and sub-directories and print the full path of file in a output txt file.
Please help me with the script or command to do so.
... (11 Replies)
I'm writing a Perl script which has its 1st step as to copy files from one directory to another directory. The Source directory has got files with extension, without extension, directories etc. But I want to copy ONLY files with no extension. The files with extensions and directories should not get... (2 Replies)
Greetings!
Been a while since I futzed around with Perl, and came upon a minor headscratcher for the community ;)
Here's the basic code which I'm trying to make tick over:#!/usr/bin/perl
use strict;
use warnings;
use diagnostics;
print " starting ";
while (-e "~/.somedir/testFile")... (9 Replies)
I have searched this quite a long time but couldn't find the right method for me to use. I need to assign read write permission to the user for specific directories and it's sub directories and files. I do not want to use ACL. I do not want to assign user the same group of that directories too.... (0 Replies)
Discussion started by: blinkingdan
0 Replies
LEARN ABOUT HPUX
zgrep
ZGREP(1) General Commands Manual ZGREP(1)NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)ZGREP(1)