hello everyone!
Very basic question for the guru's in here but anyways, I am trying to type a command that is longer than the line. What character do I use to continue my command on the next line?
Thanks in advance....
Todd (1 Reply)
I wish to enter directories which are on the HD but not part of the user hierarchy and have access to the contents of an external HD. To an advanced user this is probably a stupid question but I experimented with ~, cd, . and.. to no avail. I did check for a suitable command but couldn't find one.... (9 Replies)
Say I write something like the following:
var1=1
var2=2
for int in 1 2
do
echo "\$var$int"
done
I want the output to be:
1
2
Instead I get something like:
$var1
$var2 (2 Replies)
Hello All,
I am trying to write a script when executed, asks you for the password, and confirm password; it should save to a file and also entered password should not be in clear text on the console - should be as ****
Can somebody give me direction in writing this in shell?
Thanks
Chiru (4 Replies)
Hi everybody,
im writing a bash script, and receiving entry from a user, and i need to check if the word has any wildcards in.
do u have any ideas please .
thanks . (2 Replies)
Hi
I am new to linux, when I typed "vi FILE1" I was able to open VI editor. I added some data and I want to save the file and I tried :w but it threw me an error.
"file1" E212: Can't open file for writing
Press ENTER or type command to continue
why I am not able to save it?
I read it... (16 Replies)
Hi All,
I want to enter into C shell from Ksh remotely.
I have written code like,
remsh $rHost -l $rUser -n "source $RM_HOME/run_time/.set_env.csh;
jar -xvf $package.$extension"
But it says;
ksh: source : not found
ksh: jar : not found
Can anyone help me?
Thanks. (1 Reply)
Hi all,
I have just installed Solaris 10 on an old Fujitsu Primepower 650 which has been wiped clean. I haven't installed anything apart from the OS yet, so the machine is 99% idle.
I get long delays when logging in, first after entering the id then another long delay after entering a valid... (8 Replies)
Hi
I am looking for a unix command or a small shell script which can takes one parameter and then searches for the passed in the parameter in any or all files under say /home/dev/
Can anyone please help me on this? (3 Replies)
i am passing input parameter 'one_two' to the script , the script output should display the result as below
one_1two
one_2two
one_3two
if
then
echo " Usage : <$0> <DATABASE> "
exit 0
else
for DB in 1 2 3
do
DBname=`$DATABASE | awk -F "_" '{print $1_${DB}_$2}`
done
fi (5 Replies)
Discussion started by: only4satish
5 Replies
LEARN ABOUT CENTOS
amcryptsimple
AMCRYPTSIMPLE(8) System Administration Commands AMCRYPTSIMPLE(8)NAME
amcryptsimple - reference simple crypt program for Amanda symmetric data encryption
SYNOPSIS
amcryptsimple to be called by Amanda only
DESCRIPTION
amcryptsimple calls gpg to perform symmetric data encryption on Amanda backup. amcryptsimple will search for the gpg program in the
following directories: /usr/local/bin:/usr/bin:/usr/sbin:/bin:/sbin
amcryptsimple uses one passphrase to encrypt the Amanda data and uses the same passphrase to decrypt the Amanda backup data. amcryptsimple
uses AES256 as the symmetric cipher.
HOW TO CREATE PASSPHRASE
Store the passphrase inside the home-directory of the Amanda user ($amanda_user) and protect it with proper permissions:
echo my_secret_passphrase > ~$amanda_user/.am_passphrase
chown $amanda_user:disk ~$amanda_user/.am_passphrase
chmod 700 ~$amanda_user/.am_passphrase
NOTES
Choose a good passphrase and protect it properly. Backup data can only be restored with the passphrase. There is no backdoor.
If storing and securing passphrase in your environment presents challenges, Amanda provide public-key data encryption through amgpgcrypt.
Public-key encryption uses the public key to encrypt and uses the private key to decrypt.
SEE ALSO amanda(8), amanda.conf(5), amcrypt(8), amgpgcrypt(8), amrestore(8), gpg(1)
The Amanda Wiki: : http://wiki.zmanda.com/
AUTHOR
Kevin Till <kevin.till@zmanda.com>
Zmanda, Inc. (http://www.zmanda.com)
Amanda 3.3.3 01/10/2013 AMCRYPTSIMPLE(8)