Sponsored Content
Full Discussion: Valiavle inside variable
Top Forums Shell Programming and Scripting Valiavle inside variable Post 302331982 by Scott on Tuesday 7th of July 2009 08:03:55 PM
Old 07-07-2009
Hi.

If I understand your problem, then try:

Code:
export REQ_FILE=`....`

(I trust that the `eval...` sets the variable as you desired - i.e. that EXPORT_PATH is at least two directories deep (cut -f 3), and the file you're looking for exists... what if there is more than one file?)

Simpler is something like
Code:
export REQ_FILE=$(ls -1 ${EXPORT_PATH}/export_DR_${DR_USER}_full_data*.gz | awk -F/ '{print $NF}')

 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

ksh: A part of variable A's name is inside of variable B, how to update A?

This is what I tried: vara=${varb}_count (( vara += 1 )) Thanks for help (4 Replies)
Discussion started by: pa3be
4 Replies

2. Shell Programming and Scripting

How to replace variable inside the variable

hi sir, i need your help for this script inside /rnmucdr/ednms05/ken/xMNBDF045_Script.sql content variable like this select * from invoice where bill_date=$BILLDATE and startNum=$STARTPARTNNUM and total_partn=$TOTALPARTN if i just paste this replace with the $SCRIPT it works great,if... (31 Replies)
Discussion started by: mani_um
31 Replies

3. UNIX for Dummies Questions & Answers

passing a variable inside a variable to a function

I would like to know how to pass a variable inside a variable to a function. sample code below -------------- for x in 1 9 do check_null $C$x ##call function to check if the value is null if then echo "line number:$var_cnt,... (2 Replies)
Discussion started by: KingVikram
2 Replies

4. Shell Programming and Scripting

passing a variable inside another variable.

Any help would be great. I know this is a dumb way of doing this, but I would like to know if there is a solution doing it this way. I'm very new at this and I'd like to learn more. Thanks! :D:D count=0 while ; do echo "enter your name" read name_$count let count=count+1 done ... (2 Replies)
Discussion started by: reconflux
2 Replies

5. Shell Programming and Scripting

variable inside variable inside loop headache

Hi Gurus I have a file called /tmp/CMDB which looks like this serial: 0623AN1208 hostname: server1 model: x4100 assetID: 1234 I am writing a for loop that will go through this file line by line creating a variable of itself. Using the first iteration of the loop (i.e. the first line) as... (6 Replies)
Discussion started by: hcclnoodles
6 Replies

6. Shell Programming and Scripting

Not able to store command inside a shell variable, and run the variable

Hi, I am trying to do the following thing var='date' $var Above command substitutes date for and in turn runs the date command and i am getting the todays date value. I am trying to do the same thing as following, but facing some problems, unique_host_pro="sed -e ' /#/d'... (3 Replies)
Discussion started by: gvinayagam
3 Replies

7. Shell Programming and Scripting

evaluating a variable inside a variable

Hi there, i think im getting myself a little confused and need some help :wall: I am reading in a bunch of variables to my script from an external file and need to validate that a value has been set for each so if you can imagine, the user is required to pass in 4 values... (3 Replies)
Discussion started by: rethink
3 Replies

8. Shell Programming and Scripting

variable inside if bracket

Is this possible? The below code not working for me. dir=mydir if ; then echo "found /home/$mydir " else echo "Not found /home/$mydir" fi ---------- Post updated at 05:28 AM ---------- Previous update was at 05:25 AM ---------- Its working for me now (1 Reply)
Discussion started by: anil510
1 Replies

9. Shell Programming and Scripting

Resolve variable inside another variable

Hello Everyone, I am trying to resolve a variable inside another variable.Let me go straight to the example. Input: Query=$Table_1 Join $Table_2 (Query itself is a variable here) Now for two different cases I am assigning different values to Table_1 and Table_2 Case 1:... (14 Replies)
Discussion started by: vinay4889
14 Replies

10. Shell Programming and Scripting

To print value for a $variable inside a $variable or file

Hi guys, I have a file "abc.dat" in below format: FILE_PATH||||$F_PATH TABLE_LIST||||a|b|c SYST_NM||||${SRC_SYST} Now I am trying to read the above file and want to print the value for above dollar variables F_PATH and SRC_SYST. The problem is it's reading the dollar variables as... (5 Replies)
Discussion started by: abcabc1103
5 Replies
Alzabo::Debug(3pm)					User Contributed Perl Documentation					Alzabo::Debug(3pm)

NAME
Alzabo::Debug - Creates constants used to turn on debugging SYNOPSIS
export ALZABO_DEBUG='SQL|TRACE' ... load and run code using Alzabo ... export ALZABO_DEBUG=METHODMAKER ... load and run code using Alzabo ... DESCRIPTION
This module creates constants used by other modules in order to determine what debugging output should be generated. The interface is currently experimental. USAGE
Currently, the only way to turn on debugging is by setting the "ALZABO_DEBUG" environment variable. This variable can contain various flags, each separated by a pipe char (|). Each flag turns on different types of debugging output. These flags must be set before Alzabo is loaded, as debugging is turned on or off through the use of constants. The current flags are: * SQL Generated SQL and its associated bound variables. * TRACE A stack trace will be generated any time SQL is generated. * METHODMAKER The "Alzabo::MethodMaker" module will generate verbose output describing the methods it is creating. * REVERSE_ENGINEER The modules involved in reverse-engineering will generate output describing what it finds during reverse-engineering. * ALL Turn on all flags. For now, all debugging output is sent to "STDERR". perl v5.8.8 2007-12-23 Alzabo::Debug(3pm)
All times are GMT -4. The time now is 02:22 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy