Different behaviour when running script as source file
Hi all,
OS: Solaris 10
I've written a script to scan the oratab file and give me a list of Oracle SIDs to choose from, and obviously in order to set the ORACLE_SID environment variable from within a script for the current shell, the script must be run as a source file.
When I run it as a normal file, i.e. not a source file, it works fine:
Code:
$ ./orasid
Choose Oracle SID:
1 SIUAT
2 RMAN
SID: 1 <-- Entered 1 here
no of array elements: 2
ORACLE_SID set to: SIUAT
..although the env var is not actually set, as expected
but when I run it as a source file I get this:
Code:
$ . ./orasid
Choose Oracle SID:
1 SIUAT
2 RMAN
SID: 1
no of array elements: 0
Enter 1 to 0, SID not set
The problem seems to be the ${#ORACLE_SID[@]} construct to establish the total number of array elements. But why does this work as a regular shell script and not as a source file? Is there an alternative which works with both?
Thanks in advance, and here's the script:
Code:
#
# orasid - scan oratab for Oracle DBs and set SID
#
# usage: . orasid
#
#####################################
#
# Determine how to suppress newline with echo command.
#
N=
C=
if echo "\c" | grep c >/dev/null 2>&1; then
N='-n'
else
C='\c'
fi
ORATAB=/var/opt/oracle/oratab
#
# Loop through ORATAB
#
i=0
echo Choose Oracle SID:
cat $ORATAB | while read LINE
do
case $LINE in
\#*) ;; #comment-line in oratab
*)
(( i=i+1 ))
poss_sid=`echo $LINE | awk -F: '{print $1}' -`
if [ ! "$poss_sid" = '*' ] ; then # ignores NULL SID
ORACLE_SID[i]=$poss_sid
echo $i ${ORACLE_SID[i]}
fi
;;
esac
done
echo $N "SID: $C"
read usrsid
echo no of array elements: ${#ORACLE_SID[@]}
if [ ${usrsid} -gt ${#ORACLE_SID[@]} ]; then
echo Enter 1 to ${#ORACLE_SID[@]}, SID not set
else
ORACLE_SID=${ORACLE_SID[usrsid]}
export ORACLE_SID
echo ORACLE_SID set to: ${ORACLE_SID[usrsid]}
fi
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